我有以下程序,我希望有3个线程吸烟者等待代理。我正在尝试使用CountDown锁存器来实现这一点。
public void runThreads(){
int numofTests;
Scanner in = new Scanner(System.in);
System.out.print("Enter the number of iterations to be completed:");
numofTests = Integer.parseInt(in.nextLine());///Gets the number of tests from the user
Agent agent = new Agent();
Smoker Pam = new Smoker ("paper", "Pam");
Smoker Tom = new Smoker ("tobacco", "Tom");
Smoker Matt = new Smoker ("matches", "Matt");
for(int i = 0; i < numofTests; i++){ //passes out as many rounds as the user specifies
Pam.run();
Tom.run();
Matt.run();
agent.run();
}
出于某种原因,当我使用以下代码运行Pam.run时,它只是在latch.await上冻结,而其余的线程都没有运行。所以我的问题是我怎样才能正确地做到这一点,以便前3名吸烟者等待latch.countdown();由代理线程调用。
public class Smoker implements Runnable{
String ingredient; //This is the one ingredient the smoker starts out with
String name;
public static CountDownLatch latch = new CountDownLatch(1);
int numOfSmokes = 0; //Total number of cigs smoker smoked;
public Smoker(String ingredient1, String Name)
{
ingredient1 = ingredient;
name = Name;
}
public void run(){
try {
System.out.println(this.name + " waits on the table...");
latch.await();///waits for agent to signal that new ingredients have been passed out
} catch(InterruptedException ex) {
Thread.currentThread().interrupt();
}
System.out.println(this.name + " stops waiting and checks the table...");
checkTable();
}
答案 0 :(得分:3)
您应该创建Thread
并将Runnable
实例作为参数传递。此外,您应该调用start
函数,而不是run
。将您的代码更改为
(new Thread(Pam)).start();
//similar for others...