单个查询中的MySQL百分比

Question

到目前为止，我已经得到了这个：\

SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
       COUNT(*) 
FROM   MaintHistory
WHERE  (MaintfaultDate + 5) < MaintactionTaken 

SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
       COUNT(*) 
FROM   MaintHistory

我会添加/编辑什么，以便计算超过5天的自行车百分比

Answer 1

试试

 SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
   Concat(count(Bike_Number)*100/COUNT(*).'%' ) as percent
 FROM   MaintHistory
 WHERE  DATE_ADD(MaintfaultDate, INTERVAL +5 DAY) < MaintactionTaken