Question

我有一个问题：

INSERT INTO tx3_hu_villages (uid,vid,x,y,name,population) VALUES 
(122,2569,-29,36,'qwertzuiop',330),
(122,52915,-134,25,'asdfghjkléá',916)
ON DUPLICATE KEY UPDATE 
name=VALUES(name),population=VALUES(population);

它在MySQL Workbench中工作正常，但在PHP中我收到此错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL  server version for the right syntax to use near '' at line 1

CREATE TABLE `tx3_hu_villages` (
  `vid` int(11) unsigned NOT NULL,
  `uid` int(11) unsigned DEFAULT NULL,
  `x` smallint(6) DEFAULT NULL,
  `y` smallint(6) DEFAULT NULL,
  `name` varchar(60) DEFAULT NULL,
  `population` smallint(5) unsigned DEFAULT 0,
  PRIMARY KEY (`vid`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

没有ON DUPLICATE KEY UPDATE也能正常使用PHP。

这是PHP代码：

$sql = "INSERT INTO ".$table_name."_villages (uid,vid,x,y,name,population) VALUES ";

for($i=0;$i<count($v);$i++){

$sql.= "(".$v[$i]['uid'].",".$v[$i]['vid'].",".$v[$i]['x'].",".$v[$i]['y'].",'".$v[$i]['village']."',".$v[$i]['population']."),";

}

$sql[strlen($sql)-1] = "";

$sql.= "ON DUPLICATE KEY UPDATE name=VALUES(name),population=VALUES(population);";

echo $sql;

有什么问题？

Answer 1

执行这些多种插入的一种方法是使用像这样的PHP内爆函数

$sql = "INSERT INTO ".$table_name."_villages (uid,vid,x,y,name,population) VALUES ";

for($i=0;$i<count($v);$i++){

$temp[] = "(".$v[$i]['uid'].",".$v[$i]['vid'].",".$v[$i]['x'].",".$v[$i]['y'].",'".$v[$i]['village']."',".$v[$i]['population'].")";

}

$sql .= implode(',', $temp);

$sql.= " ON DUPLICATE KEY UPDATE name=VALUES(name),population=VALUES(population);";

echo $sql;

可能会避免与白空间相关的问题。

'重复密钥'问题

1 个答案: