Question

rechargedate |   mobile       |   amount
-------------+----------------+--------
01-07-2009   |   0103001199   |   50.00
01-07-2009   |   0103001199   |   50.00
20-07-2009   |   0103001199   |   50.00

以上是我数据的一部分，现在我想在同一天将相同数量的充值变为一行：

rechargedate  |  mobile       |  Amount
--------------+---------------+--------
01-07-2009    |  0103001199   |  50.00
20-07-2009    |  0103001199   |  20.00

我该怎么做（转换？演员？）？

Answer 1

SELECT DISTINCT columns FROM table GROUP BY columns

看起来你也需要GROUP BY

Answer 2

SELECT DISTINCT columns FROM table WHERE .....

Answer 3

也许您正在寻找distinct？

Answer 4

如果两行相同，您可以在DISTINCT之后使用SELECT关键字：

select DISTINCT rechargedate, mobile, amount FROM yourTable

如果您有以下行：

，则无效

rechargedate |   mobile       |   amount
-------------+----------------+--------
01-07-2009   |   0103001199   |  150.00
01-07-2009   |   0103001199   |   50.00
20-07-2009   |   0103001199   |   50.00

在这种情况下，您需要GROUP BY充值日期。这将为每个不同的充值日期仅获取一行，这可能并不总是您所需要的：

select rechargedate, mobile, amount FROM yourTable GROUP BY rechargedate

Answer 5

SELECT rechargedate, mobile, SUM(amount) FROM tablename
GROUP BY rechargedate, mobile

Answer 6

SELECT a.rechargedate, a.mobileno,sum(a.Amount),b.reg_dealer, 
(c.agn_code + '-' + c.agn_master_code + '-' + c.agn_state + '-' + c.agn_dealer_code), b.reg_activationdate
from recharge a, dailyregistration b, agents c
where 
substring(b.reg_dealer, 5, 6) = c.agn_dealer_code
and b.reg_id = a.mobileno
and month(a.rechargedate) = 7
group by a.rechargedate, a.mobileno, b.reg_dealer, (c.agn_code + '-' + c.agn_master_code + '-' + c.agn_state + '-' + c.agn_dealer_code), b.reg_activationdate
order by a.mobileno

如何成为一个？

6 个答案: