Question

我想将整个网站的标题放入变量中。因此，例如，我想将这三行放在一个变量中：

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

我正在为它写一个函数：

function set_header(){
         //This is where i would like to set the variable for the 3 lines I mentioned earlier
}

Answer 1

function set_header(){
echo '<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>';
}

set_header();

OR

function set_header(){
return '<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>';
}

echo set_header();

Answer 2

    function set_header(){
    $header = '<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
                <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
                <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>';
    return $header;
}

echo set_header（）;

如何将HTML标头放入PHP变量中

2 个答案: