我在Django 1.5中使用MyUser模型并通过电子邮件登录: 模型:
class MyUser(AbstractBaseUser):
email = models.EmailField(
verbose_name='email address',
max_length=255,
unique=True,
db_index=True,
)
last_name=models.CharField(max_length=30)
first_name=models.CharField(max_length=30)
second_name=models.CharField(max_length=30, blank=True)
post=models.CharField(max_length=30, blank=True)
objects = MyUserManager()
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = ['last_name','first_name','second_name','post', ....]
def get_full_name(self):
return self.email
def get_short_name(self):
return self.email
def __unicode__(self):
return self.email
def has_perm(self, perm, obj=None):
return True
def has_module_perms(self, app_label):
return True
@property
def is_staff(self):
return self.is_admin
我尝试使用django.contrib.auth.views import login:
网址:
(r'^login/$', login, {'template_name': 'enter.html'}),
观点:没有。
适用于来自经典用户模型的超级用户,而不适用于MyUser。
然后我尝试了:
视图:
def login_view(request):
username = request.POST['email']
password = request.POST['password']
user = authenticate(username=username, password=password)
if user is not None and user.is_active:
login(request, user)
return HttpResponseRedirect("/n1.html")# Redirect to a success page.
else:
return HttpResponseRedirect("/account/invalid/")# Return a 'disabled account' error message
模板:
{% if form.errors %}
<p>Something is wrong</p>
{% endif %}
<form action="" method="post">
{% csrf_token %}
<label for="email">Login:</label>
<input type="text" name="email" value="" id="email"/>
<label for="password">Password:</label>
<input type="password" name="password" value="" id="username">
<input type="submit" value="login" />
<input type="hidden" name="next" value="{{next|escape}}" />
</form>
网址:
(r'^login/$', login_view, {'template_name': 'enter.html'}),
但我收到错误login_view() got an unexpected keyword argument 'template_name'
我做错了什么?
答案 0 :(得分:5)
login_view() got an unexpected keyword argument 'template_name'
表示您的视图函数应具有template_name
参数:
def login_view(request, template_name):
'your code'
如果您不需要,请不要在urls.py中传递它:
(r'^login/$', login_view),
UPD。
您的login_view
处理您的POST方法。您可以通过这种方式重写它以在GET上呈现表单
def login_view(request):
if request.method == 'POST':
username = request.POST['email']
password = request.POST['password']
user = authenticate(username=username, password=password)
if user is not None and user.is_active:
login(request, user)
return HttpResponseRedirect("/n1.html")
return HttpResponseRedirect("/account/invalid/")
form = LoginForm()
return render(request, 'enter.html', {'login_form': LoginForm})