使用gensim
我能够从LSA中的一组文档中提取主题,但如何访问从LDA模型生成的主题?
打印lda.print_topics(10)
代码时出现以下错误,因为print_topics()
返回NoneType
:
Traceback (most recent call last):
File "/home/alvas/workspace/XLINGTOP/xlingtop.py", line 93, in <module>
for top in lda.print_topics(2):
TypeError: 'NoneType' object is not iterable
代码:
from gensim import corpora, models, similarities
from gensim.models import hdpmodel, ldamodel
from itertools import izip
documents = ["Human machine interface for lab abc computer applications",
"A survey of user opinion of computer system response time",
"The EPS user interface management system",
"System and human system engineering testing of EPS",
"Relation of user perceived response time to error measurement",
"The generation of random binary unordered trees",
"The intersection graph of paths in trees",
"Graph minors IV Widths of trees and well quasi ordering",
"Graph minors A survey"]
# remove common words and tokenize
stoplist = set('for a of the and to in'.split())
texts = [[word for word in document.lower().split() if word not in stoplist]
for document in documents]
# remove words that appear only once
all_tokens = sum(texts, [])
tokens_once = set(word for word in set(all_tokens) if all_tokens.count(word) == 1)
texts = [[word for word in text if word not in tokens_once]
for text in texts]
dictionary = corpora.Dictionary(texts)
corpus = [dictionary.doc2bow(text) for text in texts]
# I can print out the topics for LSA
lsi = models.LsiModel(corpus_tfidf, id2word=dictionary, num_topics=2)
corpus_lsi = lsi[corpus]
for l,t in izip(corpus_lsi,corpus):
print l,"#",t
print
for top in lsi.print_topics(2):
print top
# I can print out the documents and which is the most probable topics for each doc.
lda = ldamodel.LdaModel(corpus, id2word=dictionary, num_topics=50)
corpus_lda = lda[corpus]
for l,t in izip(corpus_lda,corpus):
print l,"#",t
print
# But I am unable to print out the topics, how should i do it?
for top in lda.print_topics(10):
print top
答案 0 :(得分:14)
在一些乱七八糟的事情之后,print_topics(numoftopics)
似乎ldamodel
有一些错误。所以我的解决方法是使用print_topic(topicid)
:
>>> print lda.print_topics()
None
>>> for i in range(0, lda.num_topics-1):
>>> print lda.print_topic(i)
0.083*response + 0.083*interface + 0.083*time + 0.083*human + 0.083*user + 0.083*survey + 0.083*computer + 0.083*eps + 0.083*trees + 0.083*system
...
答案 1 :(得分:8)
我认为show_topics的语法随着时间的推移而发生了变化:
show_topics(num_topics=10, num_words=10, log=False, formatted=True)
对于num_topics主题数,请返回num_words个最重要的单词(默认情况下每个主题10个单词)。
主题以列表形式返回 - 如果格式为True,则为字符串列表;如果为False,则为(概率,单词)2元组列表。
如果log为True,也将此结果输出到log。
与LSA不同,LDA中的主题之间没有自然顺序。因此,所有主题的返回num_topics&lt; = self.num_topics子集是任意的,并且可能在两次LDA训练运行之间发生变化。
答案 2 :(得分:6)
您使用的是任何日志记录吗? print_topics
按照docs中的说明打印到日志文件。
正如@ mac389所说,lda.show_topics()
是打印到屏幕的方式。
答案 3 :(得分:3)
你可以使用:
for i in lda_model.show_topics():
print i[0], i[1]
答案 4 :(得分:2)
以下是打印主题的示例代码:
def ExtractTopics(filename, numTopics=5):
# filename is a pickle file where I have lists of lists containing bag of words
texts = pickle.load(open(filename, "rb"))
# generate dictionary
dict = corpora.Dictionary(texts)
# remove words with low freq. 3 is an arbitrary number I have picked here
low_occerance_ids = [tokenid for tokenid, docfreq in dict.dfs.iteritems() if docfreq == 3]
dict.filter_tokens(low_occerance_ids)
dict.compactify()
corpus = [dict.doc2bow(t) for t in texts]
# Generate LDA Model
lda = models.ldamodel.LdaModel(corpus, num_topics=numTopics)
i = 0
# We print the topics
for topic in lda.show_topics(num_topics=numTopics, formatted=False, topn=20):
i = i + 1
print "Topic #" + str(i) + ":",
for p, id in topic:
print dict[int(id)],
print ""
答案 5 :(得分:2)
我认为将主题视为单词列表总是更有帮助的。以下代码段有助于实现该目标。我假设您已经有一个称为lda_model
的lda模型。
for index, topic in lda_model.show_topics(formatted=False, num_words= 30):
print('Topic: {} \nWords: {}'.format(idx, [w[0] for w in topic]))
在上面的代码中,我决定显示属于每个主题的前30个单词。为简单起见,我展示了我得到的第一个主题。
Topic: 0
Words: ['associate', 'incident', 'time', 'task', 'pain', 'amcare', 'work', 'ppe', 'train', 'proper', 'report', 'standard', 'pmv', 'level', 'perform', 'wear', 'date', 'factor', 'overtime', 'location', 'area', 'yes', 'new', 'treatment', 'start', 'stretch', 'assign', 'condition', 'participate', 'environmental']
Topic: 1
Words: ['work', 'associate', 'cage', 'aid', 'shift', 'leave', 'area', 'eye', 'incident', 'aider', 'hit', 'pit', 'manager', 'return', 'start', 'continue', 'pick', 'call', 'come', 'right', 'take', 'report', 'lead', 'break', 'paramedic', 'receive', 'get', 'inform', 'room', 'head']
我不太喜欢上述主题的外观,因此我通常将代码修改为如下所示:
for idx, topic in lda_model.show_topics(formatted=False, num_words= 30):
print('Topic: {} \nWords: {}'.format(idx, '|'.join([w[0] for w in topic])))
...,输出(显示前两个主题)将如下所示。
Topic: 0
Words: associate|incident|time|task|pain|amcare|work|ppe|train|proper|report|standard|pmv|level|perform|wear|date|factor|overtime|location|area|yes|new|treatment|start|stretch|assign|condition|participate|environmental
Topic: 1
Words: work|associate|cage|aid|shift|leave|area|eye|incident|aider|hit|pit|manager|return|start|continue|pick|call|come|right|take|report|lead|break|paramedic|receive|get|inform|room|head
答案 6 :(得分:1)
使用Gensim清理自己的主题格式。
soup
输出:
from gensim.parsing.preprocessing import preprocess_string, strip_punctuation,
strip_numeric
lda_topics = lda.show_topics(num_words=5)
topics = []
filters = [lambda x: x.lower(), strip_punctuation, strip_numeric]
for topic in lda_topics:
print(topic)
topics.append(preprocess_string(topic[1], filters))
print(topics)
答案 7 :(得分:0)
最近,在使用Python 3和Gensim 2.3.0时遇到了类似的问题。 print_topics()
和show_topics()
没有给出任何错误,但也没有打印任何内容。结果是show_topics()
返回一个列表。所以人们可以这样做:
topic_list = show_topics()
print(topic_list)
答案 8 :(得分:0)
您还可以将每个主题的热门词语导出到csv文件。 topn
控制每个主题下要导出的单词数。
import pandas as pd
top_words_per_topic = []
for t in range(lda_model.num_topics):
top_words_per_topic.extend([(t, ) + x for x in lda_model.show_topic(t, topn = 5)])
pd.DataFrame(top_words_per_topic, columns=['Topic', 'Word', 'P']).to_csv("top_words.csv")
CSV文件格式如下
Topic Word P
0 w1 0.004437
0 w2 0.003553
0 w3 0.002953
0 w4 0.002866
0 w5 0.008813
1 w6 0.003393
1 w7 0.003289
1 w8 0.003197
...
答案 9 :(得分:0)
****This code works fine but I want to know the topic name instead of Topic: 0 and Topic:1, How do i know which topic this word comes in**?**
for index, topic in lda_model.show_topics(formatted=False, num_words= 30):
print('Topic: {} \nWords: {}'.format(idx, [w[0] for w in topic]))
Topic: 0
Words: ['associate', 'incident', 'time', 'task', 'pain', 'amcare', 'work', 'ppe', 'train', 'proper', 'report', 'standard', 'pmv', 'level', 'perform', 'wear', 'date', 'factor', 'overtime', 'location', 'area', 'yes', 'new', 'treatment', 'start', 'stretch', 'assign', 'condition', 'participate', 'environmental']
Topic: 1
Words: ['work', 'associate', 'cage', 'aid', 'shift', 'leave', 'area', 'eye', 'incident', 'aider', 'hit', 'pit', 'manager', 'return', 'start', 'continue', 'pick', 'call', 'come', 'right', 'take', 'report', 'lead', 'break', 'paramedic', 'receive', 'get', 'inform', 'room', 'head']