Question

我想创建一个javascript，点击后会将anotif的值更改为0：

Approved:<?php if($anotif<1){
    echo 0;
} else { 
    echo '<a class="anotif" onClick="validator()" href="?anotif">'.$anotif.'</a>';
} ?><br/>

但我不知道怎么做，考虑到我在javascript中是如此新鲜。我已经搜索了一下，但我找不到答案。

function validator(){
    if(document.anotif.clicked){ // I'm not really sure if this is correct.
        // if clicked, change value to zero
}

更确切地说，我希望它在点击后看起来像这样：从：批准：3 至：批准：0

Approved:<?php if($anotif<1){
    echo 0;
} else { 
    echo '<a class="anotif" onClick="validator()" href="?anotif">'.$anotif.'</a>';
} ?><br/>

此代码将引导我使用？anotif来查看表中数据库中的某些数据。一旦获得批准：

被点击，它必须在我移动到另一页的同时设置为零。

问题是系统需要刷新才能将其设置为0。

以下是代码的其余部分：

$firstname =  getuserfield('txtFname');
$lastname = getuserfield('txtLname');
echo 'Hello '.$firstname.' '.$lastname.'.<br/>';

$anotif = 0;
$dnotif = 0;
$anotif = $anotif + getuserfield('approved_notif');
$dnotif = $dnotif + getuserfield('disapproved_notif');
?>
<h3>Notifications:</h3>
Approved:<?php if($anotif<1){echo 0;} else { echo '<a class="anotif" onClick="validator(this);" href="?anotif">'.$anotif.'</a>';}?><br/> //problem is over here
<?php 
if(isset($_GET['anotif'])) {
    $query = "SELECT * FROM hrf_leave WHERE empid = '$empid' AND formStatus = 1 AND checked = 0";
    $query_run = mysql_query($query) or die($query."<br/><br/>".mysql_error());
    echo "<table border=1>
    <tr>
    <th>Type of Leave</th>
    <th>Specific Reason</th>
    <th>Date From</th>
    <th>Date To</th>
    <th>Number of Days</th>
    </tr>";
    echo "<tr>";
    while($record = mysql_fetch_array($query_run)){ 
        $leave_id = $record['leave_id'];
        echo "<td>" . $record['type_of_leave'] . "</td>";
        echo "<td>" . $record['specific_reason'] . "</td>";
        echo "<td>" . $record['date_from'] . "</td>";
        echo "<td>" . $record['date_to'] . "</td>";
        echo "<td>" . $record['num_of_days'] . "</td>";
        echo "</tr>";
        $query2 = "UPDATE hrf_leave SET checked=1 WHERE leave_id = $leave_id";
        if($query_run2 = mysql_query($query2)){ 
            $anotif = 0;
            $query3 = "UPDATE hrms_emp_info SET approved_notif=$anotif WHERE empid = $empid";
            if($query_run3 = mysql_query($query3)){
            }
        }
    }
    echo "</table>";
}
?>
Disapproved:<?php if($dnotif<1){echo 0;} else { echo '<a href="?dnotif">'.$dnotif.'</a><br/>';} ?> //and here
<?php
if(isset($_GET['dnotif'])) {
    $query = "SELECT * FROM hrf_leave WHERE empid = '$empid' AND formStatus = 2 AND checked=0"; 
    $query_run = mysql_query($query);
    echo "<table border=1>
    <tr>
    <th>Type of Leave</th>
    <th>Specific Reason</th>
    <th>Date From</th>
    <th>Date To</th>
    <th>Number of Days</th>
    </tr>";
    echo "<tr>";
    while($record = mysql_fetch_array($query_run)){
        $leave_id = $record['leave_id'];
        echo "<td>" . $record['type_of_leave'] . "</td>";
        echo "<td>" . $record['specific_reason'] . "</td>";
        echo "<td>" . $record['date_from'] . "</td>";
        echo "<td>" . $record['date_to'] . "</td>";
        echo "<td>" . $record['num_of_days'] . "</td>";
        echo "</tr>";
        $query2 = "UPDATE hrf_leave SET checked=1 WHERE leave_id = $leave_id";
        if($query_run2 = mysql_query($query2)){ 
            $dnotif = $dnotif-1;
            $query3 = "UPDATE  hrms_emp_info SET disapproved_notif=$dnotif WHERE empid = $empid";
            if($query_run3 = mysql_query($query3)){ 
            }
        }
    }
    echo "</table>";
}

Answer 1

你可以改变你的锚点：

<a class="anotif" onClick="return validator(this)" href="?anotif">

然后像这样更改validator()函数：

function validator(element)
{
    // element is clicked already, so you can change its value

    element.innerHTML = '0';

    // prevent click from changing page
    return false;
}

~~但是，真正的问题是页面将更改为?anotif，无论你改变什么都会浪费精力。~~ 更新了代码，以防止点击更改页面，只是将数字减少为“0”。

删除点击值

1 个答案: