您好我的问题如下： 我根据结果页面分了.. 问题是afiserea结果 我有以下代码：
<?php
include('ttt_files/paginare.php');
$rezultate_pe_pagina = '2';
$statement = "`anunt_standard` where `activat` = 0 AND prs_prv='$filtru_p' ";
/* Inceputul stabiliri functiei numaratorelor */
$page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
$limit = $rezultate_pe_pagina;
$startpoint = ($page * $limit) - $limit;
//Query pentru afisere si paginare
/* Sfarsitul stabiliri functiei numaratorelor */
$url = "{$server_url}anunturi/f/{$_GET['f']}/page/";
echo "<div id='asezare_butoane'>".pagination($statement,$limit,$page,$url)."</div>";
//afiseaza inregistrarile platite
$query_pay = mysql_query("
SELECT * FROM {$statement} AND activat_plata = '1'
AND sters = '0' ORDER BY data_adaugare DESC LIMIT {$startpoint} ,
{$limit}");
echo "
<table border='0' width='950px'
style='border-collapse:separate; border-spacing:0px 5px;'>";
$i = 0;
while ($row = mysql_fetch_assoc($query_pay)) {
include('continut_platit.php');
}
echo "</table>";
//afiseaza inregistrarile normale
$query = mysql_query("
SELECT * FROM {$statement} AND sters = '0'
AND activat_plata = '0'
ORDER BY data_adaugare DESC
LIMIT {$startpoint} , {$limit}");
echo "
<table border='0' width='950px'
style='border-collapse:separate; border-spacing:0px 5px;'>";
$i = 0;
while ($row = mysql_fetch_assoc($query)) {
include('continut.php');
}
echo "</table>";
//afiseaza inregistrarile sterse
$query_del = mysql_query("
SELECT * FROM {$statement}
AND sters = '1'
ORDER BY data_adaugare DESC
LIMIT {$startpoint} , {$limit}");
echo "<table border='0' width='950px' style='border-collapse:separate; border-spacing:0px 5px;'>";
$i = 0;
while ($row = mysql_fetch_assoc($query_del)) {
include('continut_sters.php');
}
echo "</table>";
?>
问题是它每页不显示2个结果，因为它现在设置显示每个查询的结果2，即粘贴总共6个结果： 2 - $ query_pay 2 - $查询 2 - $ query_del 但是打电话弄清楚如何让它只显示2例如是第一页如果添加2条记录'付费'只显示在那些2上..或者如果你只有2条记录，查询只显示那些2 :( 分页功能
<?php
function pagination($query, $per_page = 10,$page = 1, $url = '?'){
$query = "SELECT COUNT(*) as `num` FROM {$query}";
$row = mysql_fetch_array(mysql_query($query));
$total = $row['num'];
$adjacents = "2";
$page = ($page == 0 ? 1 : $page);
$start = ($page - 1) * $per_page;
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total/$per_page);
$lpm1 = $lastpage - 1;
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<ul class='pagination'>";
//$pagination .= "<li class='details'>Pagina $page din $lastpage</li>";
if ($lastpage < 7 + ($adjacents * 2))
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<li><a class='current'>$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter/'>$counter</a></li>";
}
}
elseif($lastpage > 5 + ($adjacents * 2))
{
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<li><a class='current'>$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter/'>$counter</a></li>";
}
$pagination.= "<li class='dot'>...</li>";
$pagination.= "<li><a href='{$url}$lpm1/'>$lpm1</a></li>";
$pagination.= "<li><a href='{$url}$lastpage/'>$lastpage</a></li>";
}
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<li><a href='{$url}1/'>1</a></li>";
$pagination.= "<li><a href='{$url}2/'>2</a></li>";
$pagination.= "<li class='dot'>...</li>";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<li><a class='current'>$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter/'>$counter</a></li>";
}
$pagination.= "<li class='dot'>..</li>";
$pagination.= "<li><a href='{$url}$lpm1/'>$lpm1</a></li>";
$pagination.= "<li><a href='{$url}$lastpage/'>$lastpage</a></li>";
}
else
{
$pagination.= "<li><a href='{$url}1/'>1</a></li>";
$pagination.= "<li><a href='{$url}2/'>2</a></li>";
$pagination.= "<li class='dot'>..</li>";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<li><a class='current'>$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter/'>$counter</a></li>";
}
}
}
if ($page < $counter - 1){
$pagination.= "<li><a href='{$url}$next/'>Urmatoarea</a></li>";
//$pagination.= "<li><a href='{$url}page=$lastpage'>Ultima</a></li>";
}else{
$pagination.= "<li><a class='current'>Urmatoarea</a></li>";
//$pagination.= "<li><a class='current'>Ultima</a></li>";
}
$pagination.= "</ul>\n";
}
return $pagination;
}
?>
我想要计算上面的总结果，并创造一个nustiu海报的条件，但如何设置条件。 或者将3放在查询结果和数字之上，然后我在3:01收集并分享他们的工作呢？但是去一个功能而不知道如何思考
mysql_query("SELECT u.* FROM (
(SELECT * FROM anunt_standard WHERE `activat_plata`='1' AND `sters`='0' AND `activat`='0' ORDER BY data_adaugare DESC)
UNION
(SELECT * FROM anunt_standard WHERE `activat_plata`='0' AND `sters`='0' AND `activat`='0' ORDER BY data_adaugare DESC)
UNION
(SELECT * FROM anunt_standard WHERE `sters`='1' AND `activat`='0' ORDER BY data_adaugare DESC)
) As u LIMIT {$startpoint} , {$limit}")or die(mysql_error());
感谢您的想法，但问题是他们无法按您想要的顺序显示...我的意思是我写的没有：
ORDER BY data_adaugare DESC
答案 0 :(得分：0)
如果您熟悉SQL中的UNION，则可能需要尝试使用LIMIT x，y创建单个查询。如果您之前没有使用过UNION，请查看http://www.w3schools.com/sql/sql_union.asp。
你会想要这样的东西：
SELECT u.* FROM (
(SELECT... 1st query)
UNION
(SELECT... 2nd query)
UNION
(SELECT... 3rd query)
) AS u LIMIT {$startpoint} , {$limit}
在回复您的第二篇文章时，UNION会对一组行进行操作，这会产生不可预测的排序。你想在UNION的末尾加上“ORDER BY”。
另一种选择是将每个选择包含在另一个选择中，这似乎很愚蠢，但它使排序工作。请注意，UNION ALL允许重复结果，因此如果任何联合查询返回同一行，则会重复该行。
SELECT u.* FROM (
SELECT * FROM (SELECT * FROM anunt_standard
WHERE `activat_plata`='1' AND `sters`='0' AND `activat`='0'
ORDER BY data_adaugare DESC) A
UNION ALL
SELECT * FROM (SELECT * FROM anunt_standard
WHERE `activat_plata`='0' AND `sters`='0' AND `activat`='0'
ORDER BY data_adaugare DESC) B
UNION ALL
SELECT * FROM (SELECT * FROM anunt_standard
WHERE `sters`='1' AND `activat`='0'
ORDER BY data_adaugare DESC) C
) As u LIMIT {$startpoint} , {$limit}