我正在Eclipse中编写Java代码来创建一个Android浏览器,当按下浏览器的Go按钮时,它会通过套接字与服务器通信。我已经看过几个例子,但仍然不知道我的代码有什么问题。我有正确的IP地址,我在代码的服务器和客户端使用相同的端口号。这是客户端代码减去import语句:
public class MainActivity3 extends Activity {
EditText URLText;
Button GoButton;
WebView Browser;
int SERVERPORT = 33333;
String servernum = "10.215.23.109";
private boolean connected = true;
private class MyWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_activity3);
URLText = (EditText) findViewById(R.id.URL);
GoButton = (Button) findViewById(R.id.Go);
Browser = (WebView) findViewById(R.id.WebEngine);
Browser.loadUrl("http://www.google.co.in/");
GoButton.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Browser.setWebViewClient(new MyWebViewClient());
Thread cThread = new Thread(new ClientThread());
cThread.start();
Browser.loadUrl("http://" + URLText.getText().toString());
}
});
}
public class ClientThread implements Runnable {
@Override
public void run() {
try {
Log.d("ClientActivity", "C: Connecting...");
Socket socket = new Socket(servernum, SERVERPORT);
} catch (UnknownHostException e) {
System.err.println(e);
} catch (IOException e) {
System.err.println(e);
}
}
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main_activity3, menu);
return true;
}
}
}
这是服务器代码:
public static void main(String[] args) throws IOException {
int port = 33334;
ServerSocket serverSocket = new ServerSocket(port);
System.out.println("Server socket created at port # "+ port );
Socket socket = serverSocket.accept();
System.out.println("Socket accepted");
System.out.println("Output created");
socket.close();
serverSocket.close();
}
这基本上是一个测试代码,以确保手机将连接到服务器。当我在我的Linux终端上运行它时,它只输出“在端口#33334创建的服务器套接字”并等待手机连接从未发生的端口,即使我反复按下浏览器,这让我相信我的代码的客户端出了问题。
有人可以帮我解决这个问题吗?
答案 0 :(得分:0)
这与this post非常相似。
您可以使用DefaultHttpClient直接与服务器通信,而不是创建WebView:
try{
DefaultHttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://10.215.23.109:33333");
HttpResponse response = client.execute(request);
}catch(Exception e){
// Handle the exception
e.printStackTrace();
}