此代码几乎完全是从scipy.org cookbook recipe输入的,我还不能注意到任何拼写错误,所以代码可能是oud?为什么这段代码正确解析数字但是KeyWord()和QuotedString()方法失败?
#use the Regex element to rapidly detect strings representing numbers:
from re import VERBOSE
number = Regex(r"""
[+-]? #optional sign
(
(?:\d+(?P<float1>\.\d*)?) # match 2 or 2.02
| # or
(?P<float2>\.\d+)? # match .02
)
(?P<float3>[Ee][+-]?\d+)? #optional exponent
""", flags=VERBOSE
)
# a function to convert this string into python float or integer and set a
# parseAction to tell pyparsing to automatically convert a number when it finds
# one:
def convert_number(t):
"""Convert a string matching a number to a python number"""
print "Converting " + str(t)
if t.float1 or t.float2 or t.float3:
return [float(t[0])]
else:
return [int(t[0])]
#try:
# return [int(t[0])]
#except:
# return t
number.setParseAction(convert_number)
# create a list of element converting strings to python objects:
from numpy import NAN
pyvalue_list = [
number,
Keyword('True').setParseAction(replaceWith(True)),
Keyword('False').setParseAction(replaceWith(False)),
Keyword('NAN', caseless=True).setParseAction(replaceWith(NAN)),
Keyword('None').setParseAction(replaceWith(None)),
QuotedString('"""', multiline=True),
QuotedString("'''", multiline=True),
QuotedString('"'),
QuotedString("'"),
]
pyvalue = MatchFirst( e.setWhitespaceChars(' \t\r') for e in pyvalue_list)
根据配方我的输出应该是:
>>> test2 = '''
>>> 1 2 3.0 0.3 .3 2e2 -.2e+2 +2.2256E-2
>>> True False nan NAN None
>>> "word" "two words"
>>> """'more words', he said"""
>>> '''
>>> print pyValue.searchString(test2)
[[1], [2], [3.0], [0.29999999999999999], [0.29999999999999999], [200.0], [-20.0], [0.022256000000000001],
[True], [False], [nan], [nan], [None], ['word'], ['two words'], ["'more words', he said"]]
但是我得到了ValueError:对于带有基数为10的int()的无效文字:''所以我添加了一个print语句来帮助调试,这里是终端会话:
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import ConfigNumParser as parser
>>> test2 = '''
... 1 2 3.0 0.3 .3 2e3 -.2e+2 +2.2256E-2
... True False nan NAN None
... "word" "two words"
... """'more words', he daid"""
... '''
>>> print parser.pyvalue.searchString(test2)
Converting ['1']
Converting ['2']
Converting ['3.0']
Converting ['0.3']
Converting ['.3']
Converting ['2e3']
Converting ['-.2e+2']
Converting ['+2.2256E-2']
Converting ['']
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python27\Lib\site-packages\pyparsing.py", line 1099, in searchString
return ParseResults([ t for t,s,e in self.scanString( instring, maxMatches ) ])
File "C:\Python27\Lib\site-packages\pyparsing.py", line 1036, in scanString
nextLoc,tokens = parseFn( instring, preloc, callPreParse=False )
File "C:\Python27\Lib\site-packages\pyparsing.py", line 871, in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File "C:\Python27\Lib\site-packages\pyparsing.py", line 2451, in parseImpl
ret = e._parse( instring, loc, doActions )
File "C:\Python27\Lib\site-packages\pyparsing.py", line 897, in _parseNoCache
tokens = fn( instring, tokensStart, retTokens )
File "C:\Python27\Lib\site-packages\pyparsing.py", line 660, in wrapper
ret = func(*args[limit[0]:])
File "ConfigNumParser.py", line 33, in convert_number
return [int(t[0])]
ValueError: invalid literal for int() with base 10: ''
所以在搜索了几个建议后,我添加了你在上面的注释区域中看到的try-catch。结果现在是:
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import ConfigNumParser as parser
>>> test2 = '''
... 1 2 3.0 0.3 .3 2e3 -.2e+2 +2.2256E-2
... True False nan NAN None
... "word" "two words"
... """'more words', he daid"""
... '''
>>> print parser.pyvalue.searchString(test2)
Converting ['1']
Converting ['2']
Converting ['3.0']
Converting ['0.3']
Converting ['.3']
Converting ['2e3']
Converting ['-.2e+2']
Converting ['+2.2256E-2']
Converting ['']
Converting ['']
Converting ['']
<deleted 65+ more of these>
Converting ['']
Converting ['']
Converting ['']
[[1], [2], [3.0], [0.3], [0.3], [2000.0], [-20.0], [0.022256], [''], [''], [''], [''], [''], [''], [''], [''], [''], [''], [''], [''], ['']]
>>>
我继续搜索&amp;学习,我认为向专业人士发布问题将有助于我和其他人。
此致 比尔
答案 0 :(得分:2)
我还没有注意到任何错字
...噢...
(?P<float2>\.\d+)?
应该是
(?P<float2>\.\d+)
修正了它。