Question

嘿我在java中尝试基于What is the best regular expression to check if a string is a valid URL?的网址验证，但由于某种原因它无效。建议？

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class urlValidate {

    /**
     * @param args
     */
    public static void main(String[] args) {
        test_url("http://brb/", false);
            test_url("https://localserver/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", false);
    test_url("https://www.google.com/", true);
    test_url("https://www.google.co.uk/projects/my%20folder/test.php", false);
    test_url("https://myserver.localdomain/", true);
    test_url("https://192.168.1.120/projects/index.php/", false);
    test_url("https://192.168.1.1/", true);
    test_url("https://projectpier-server.localdomain/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", false);
    test_url("https://2.4.168.19/project-pier?c=test&a=b", false);
    test_url("https://localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", false);
    test_url("https://user:password@localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", false);
    test_url("myserver",false);
    test_url("https://tomcat:8080/",true);
    test_url("https://facebook.com",false);
}

public static void test_url(String url, boolean expected) {
    boolean valid = isURLValid(url, true);
    String out = "URL Valid?: " + (valid ? "yes" : "no") + " for URL: "
            + url + ". Expected: " + (expected ? "yes" : "no") + ". ";
    if (valid == expected) {
        out += "PASS\n";
    } else {
        out += "FAIL\n";
    }
    System.out.println(out);
}

public static boolean isURLValid(String url, boolean forcehttps) {
    String regex = "";
    if (forcehttps) {
        regex = "/^(https):\\/\\/";
    } else {
        regex = "/^(https?):\\/\\/";
    }
    regex += "((([a-z0-9]\\.|[a-z0-9][a-z0-9-]*[a-z0-9]\\.)*"
            + "[a-z][a-z0-9-]*[a-z0-9]"
            + "|((\\d|[1-9]\\d|1\\d{2}|2[0-4][0-9]|25[0-5])\\.){3}"
            + "(\\d|[1-9]\\d|1\\d{2}|2[0-4][0-9]|25[0-5])"
            + ")(:\\d+)?)"
            + "(#([a-z0-9$_\\.\\+!\\*\\'\\(\\),;:@&=-]|%[0-9a-f]{2})*)?(\\/)"
            + "$/i";

    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(url); // get a matcher object
    return m.matches();
}

}

Answer 1

正则表达式最初用斜杠包装（用作分隔符，这是PHP中PCRE所必需的）。 Java不使用这些。

if (forcehttps) {
    regex = "^(https):\\/\\";
} else {
    regex = "^(https?):\\/\\";
}

最后的/i也是不受欢迎的。相反，写

Pattern p = Pattern.compile(regex, Pattern.CASE_INSENSITIVE)

Answer 2

您可以使用Apache commons-validator api。有一个名为 UrlValidator 的类，或者类似的东西看看这个：http://commons.apache.org/validator/
我不了解很多正则表达式，所以我对这个问题没什么帮助祝你好运。

Answer 3

虽然将regex写入URL验证不是问题，但为什么不只是使用java.io.URL类？只需创建URL的实例，如下所示：new URL(spec)如果语法错误，它将抛出MalformedURLExcption。

java中的URL验证

3 个答案: