Question

我有这个查询。它创建了一个日历，用于在医疗索赔中与DOS进行比较，以计算不同的天数。

当我运行它时，我似乎放下了几行，这些行不会出现在我的结果中。

任何人都可以看到为什么这些行不会在此查询中计算？

ICN From Date of Service To Date of Service Detail Status Code
12345 20121102 12:00:00 20121103 12:00:00 P
12345 20121102 12:00:00 20121103 12:00:00 P
12345 20121102 12:00:00 20121103 12:00:00 P
12345 20121102 12:00:00 20121103 12:00:00 D
12345 20121102 12:00:00 20121103 12:00:00 D
12345 20121102 12:00:00 20121103 12:00:00 D
12345 20121102 12:00:00 20121103 12:00:00 D
12345 20121102 12:00:00 20121103 12:00:00 D

CREATE TABLE #Calendar1(Dt DATETIME NOT NULL PRIMARY KEY);
;WITH cte AS
(
    SELECT CAST('20120101' AS DATETIME) AS c 
    UNION ALL
    SELECT DATEADD(dd,1,c) FROM cte 
    WHERE c < '20131231'
)
INSERT INTO #Calendar1 SELECT c FROM cte OPTION  (MAXRECURSION 1);


SELECT
    ICN,
    COUNT(DISTINCT Dt) AS Days
FROM
    AllOPBYDOS s
    INNER JOIN #Calendar1 c ON
        s.[from Date of service] >= c.Dt AND s.[to Date of service] < c.Dt+1
--Where [Detail Status Code] = 'p'

GROUP BY
    ICN;

Answer 1

当我在SQL Server 2008上运行日历查询时，它只生成一行。我想你想要：

INSERT INTO #Calendar1 SELECT c FROM cte OPTION  (MAXRECURSION 0);

对于已删除的行，您确定它们的日历范围内有日期吗？你应该做一个左外连接并检查极端情况：

SELECT ICN, COUNT(DISTINCT Dt) AS Days,
       sum(case when [from Date of service] not between const.mindt and const.maxdt or
                     [to Date of service] not between const.mindt and const.maxdt
                then 1
                else 0
           end) as OutOfRangeRecords
FROM AllOPBYDOS s left outer JOIN
     #Calendar1 c
     ON s.[from Date of service] >= c.Dt AND s.[to Date of service] < c.Dt+1 cross join
     (select MAX(dt) as maxdt, MIN(dt) as mindt from #Calendar1) const
GROUP BY ICN;

SQL查询丢弃所需的行

1 个答案: