Question

这是我的Windows批处理文件：

FOR /F %%a IN ('git rev-parse --abbrev-ref HEAD') DO SET branchName = %%a
FOR /F %%a IN ('git rev-list --max-count^=1 %branchName%') DO SET localCommitId = %%a
FOR /F %%a IN ('git rev-list --max-count^=1 origin/%branchName%') DO SET remoteCommitId = %%a

@ECHO branchName = %branchName%
@ECHO localCommitId = %localCommitId%
@ECHO remoteCommitId = %remoteCommitId%

这是我运行时看到的输出：

>FOR /F %a IN ('git rev-parse --abbrev-ref HEAD') DO SET branchName = %a

>SET branchName = develop

>FOR /F %a IN ('git rev-list --max-count=1 develop') DO SET localCommitId = %a

>SET localCommitId = e4375fa4753b3956e1454020a812cc7591cf606e

>FOR /F %a IN ('git rev-list --max-count=1 origin/develop') DO SET remoteCommitId = %a

>SET remoteCommitId = e4375fa4753b3956e1454020a812cc7591cf606e

branchName = develop
localCommitId =
remoteCommitId =

我不明白为什么localCommitId和remoteCommitId为空，尽管打印的SET命令将它们设置为非空字符串。

我想git命令的功能与问题无关，因为如果我用ver替换它们，我会遇到同样的问题。

Answer 1

我还会添加一些解释。如果您输入set branch，则会看到branchName = develop。这意味着变量实际上将使用%branchName %调用，并且会给出值develop

更正了以下代码。

FOR /F %%a IN ('git rev-parse --abbrev-ref HEAD') DO SET branchName=%%a
FOR /F %%a IN ('git rev-list --max-count^=1 %branchName%') DO SET localCommitId=%%a
FOR /F %%a IN ('git rev-list --max-count^=1 origin/%branchName%') DO SET remoteCommitId=%%a

@ECHO branchName = %branchName%
@ECHO localCommitId = %localCommitId%
@ECHO remoteCommitId = %remoteCommitId%

用于设置变量的多个for循环，但只有第一个产生效果

1 个答案: