当我点击侧边栏列表中的项目时,我想滚动到相应的.cinematography_box,我有这个标记:
就像列表中的第一项>转到>第一,.cinematography_box div等等,第二,第三等
实现这一目标的最佳方式是什么?
<div id="sidebar" class="clearfix">
<ul>
<li>
<a id="aboutlink" href="javascript:void(0)" >CINEMATOGRAPHY LIST</a>
</li>
<li>
<a href="javascript:void(0)">FIRST ITEM</a>
</li>
<li>
<a href="javascript:void(0)">SECOND ITEM</a>
</li>
<li>
<a href="javascript:void(0)">THIR ITEM</a>
</li>
</ul>
</div>
<div id="gallery" class="cinematography clearfix">
<div class="cinematography_box clearfix">
<div class="cinematography_item">
</div>
<div class="cinematography_info">
<p>Lorem Ipsum</p>
</div>
</div>
<div class="cinematography_box clearfix">
<div class="cinematography_item">
</div>
<div class="cinematography_info">
<p>Lorem Ipsum</p>
</div>
</div>
<div class="cinematography_box clearfix" >
<div class="cinematography_item">
</div>
<div class="cinematography_info">
<p>Lorem Ipsum</p>
</div>
</div>
</div>
答案 0 :(得分:1)
定义每个元素:
<li data-target="one">
<a href="javascript:void(0)">THIR ITEM</a>
</li>
<div class="cinematography_info" data-pos="one">
<p>Lorem Ipsum</p>
</div>
使用jQuery你可以这样做:
$(document).ready(function(){
$("li").click(function() {
scrollTo($(this).attr("data-target"));
});
});
function scrollTo(target){
var tagScroll = $(".cinematography_info[data-pos='"+ target+"']");
$('html,body').animate({scrollTop: tagScroll .offset().top},'slow');
}
参见我做过的例子: http://jsfiddle.net/NfwEv/9/
答案 1 :(得分:0)
首先,提供三个div
代码ID,例如item1
,item2
,item3
。
这样,您可以将a
代码更改为:
<li>
<a href="#item1">FIRST ITEM</a>
</li>
<li>
<a href="#item2">SECOND ITEM</a>
</li>
<li>
<a href="#item3">THIR ITEM</a>
</li>