Question

我正在使用以下代码使用uisearchbar，tableview和JSON Web服务进行搜索。目前的问题是，虽然应用程序正在搜索并在tableview中显示数据，但是在搜索栏中发生每个文本更改后，它都会进行搜索。我希望它只在用户触摸搜索按钮后进行搜索。当它在uisearch文本字段中的每次更改中查询Web时，它似乎陷入困境。

这是我在寻找的方式：

-(void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{

    NSString *searchQuery = [NSString stringWithFormat:@"http://api.****/%@",searchText];

    NSString *jsonString = [NSString
                            stringWithContentsOfURL:[NSURL URLWithString:searchQuery]
                            encoding:NSStringEncodingConversionAllowLossy|NSUTF8StringEncoding
                            error:nil];

    NSMutableArray *itemsTMP = [[NSMutableArray alloc] init];

    SBJSON *parser = [[SBJSON alloc] init];
    NSDictionary *results = [parser objectWithString:jsonString error:nil];

    itemsTMP = [results objectForKey:@"results"];

    //   [self setDisplayItems:[results objectForKey:@"results"]];

    [self setAllItems:[itemsTMP copy]];
    self.displayItems = [itemsTMP copy];

    int a =   [displayItems count];
    NSString *countString = [NSString stringWithFormat:@"results %d",a];
    countLabel.text = countString;

    [self.tableView reloadData];


}

我想也许代码应该移到

-(void) searchBarSearchButtonClicked:(UISearchBar *)aSearchBar {

    [self.searchBar resignFirstResponder];

    return;
    // searchBar resigns after search clicked

}

但不确定如何将:(NSString *)searchText添加到此方法

感谢您的帮助

Answer 1

只需将textDidChange代码转换为searchBarSearchButtonClicked方法即可解决您的问题。

-(void) searchBarSearchButtonClicked:(UISearchBar *)aSearchBar {

    [self.searchBar resignFirstResponder];

    NSString *searchQuery = [NSString stringWithFormat:@"http://api.****/%@",aSearchBar.text];

    NSString *jsonString = [NSString
                            stringWithContentsOfURL:[NSURL URLWithString:searchQuery]
                            encoding:NSStringEncodingConversionAllowLossy|NSUTF8StringEncoding
                            error:nil];

    NSMutableArray *itemsTMP = [[NSMutableArray alloc] init];

    SBJSON *parser = [[SBJSON alloc] init];
    NSDictionary *results = [parser objectWithString:jsonString error:nil];

    itemsTMP = [results objectForKey:@"results"];

    //   [self setDisplayItems:[results objectForKey:@"results"]];

    [self setAllItems:[itemsTMP copy]];
    self.displayItems = [itemsTMP copy];

    int a =   [displayItems count];
    NSString *countString = [NSString stringWithFormat:@"results %d",a];
    countLabel.text = countString;

    [self.tableView reloadData];

    return;
    // searchBar resigns after search clicked

}

如何阻止uisearch立即搜索？

1 个答案: