Question

我想在每20个字符后放置\ n ......

My_string = "aaaaaaaaaaaaaaaaaaabbbbbbbbbbbbbbbbbbbbccccccccccccccccccccddddddddddddddddddddeeeeeeeeeeeeeeeeeeeeffffffffffffffffffff"

我试过这个：a = "\n".join(re.findall("(?s).{,20}", My_string))[0:-1]

我什么时候打印像：

print '''
              ---------------------------------------------------------------
               Value of a is 
            %s
              ---------------------------------------------------------------
        ''' % a

输出：

     ---------------------------------------------------------------
                          Value of a is
                          aaaaaaaaaaaaaaaaaaab
bbbbbbbbbbbbbbbbbbbc
cccccccccccccccccccd
ddddddddddddddddddde
eeeeeeeeeeeeeeeeeeef
fffffffffffffffffff
                          ---------------------------------------------------------------

我希望输出如下：

           ---------------------------------------------------------------
           Value of a is 
           aaaaaaaaaaaaaaaaaaab
           bbbbbbbbbbbbbbbbbbbc
           cccccccccccccccccccd
           ddddddddddddddddddde
           eeeeeeeeeeeeeeeeeeef
           fffffffffffffffffff
           ---------------------------------------------------------------

Answer 1

您想要创建所有行的列表，包括预定义和包装，然后在每个行的前面添加空间标识（最好在一个步骤中以避免重复的代码），然后将所有行连接到单个字符串中。

虽然正则表达式可以解决问题，但请查看一个很好的标准模块textwrap，它允许您换行：

import textwrap

My_string = "aaaaaaaaaaaaaaaaaaabbbbbbbbbbbbbbbbbbbbccccccccccccccccccccddddddddddddddddddddeeeeeeeeeeeeeeeeeeeeffffffffffffffffffff"


print '\n'.join('              {0}'.format(line) for line in [
                '---------------------------------------------------------------',
                'Value of a is'] + textwrap.fill(My_string, 20).split('\n') +
                ['---------------------------------------------------------------'])

打印

              ---------------------------------------------------------------
              Value of a is
              aaaaaaaaaaaaaaaaaaab
              bbbbbbbbbbbbbbbbbbbc
              cccccccccccccccccccd
              ddddddddddddddddddde
              eeeeeeeeeeeeeeeeeeef
              fffffffffffffffffff
              ---------------------------------------------------------------

Answer 2

试试这个：

# -*- encoding: utf-8 -*-
import re

My_string = "aaaaaaaaaaaaaaaaaaabbbbbbbbbbbbbbbbbbbbccccccccccccccccccccddddddddddddddddddddeeeeeeeeeeeeeeeeeeeeffffffffffffffffffff"
split="\n     "
a = split.join(re.findall("(?s).{,20}", My_string))[0:-1]



print '''     ---------------------------------------------------------------
     Value of a is 
     %s ---------------------------------------------------------------''' % a

看起来可以满足您的要求

在64个字符后将字符串放入新行

2 个答案: