Question

我尝试使用以下代码创建触发器。

CREATE OR REPLACE TRIGGER MYTABLE_TRG 
BEFORE INSERT ON MYTABLE 
FOR EACH ROW 
BEGIN 
 select MYTABLE_SEQ.nextval into :new.id from dual; 
END;

我收到错误

Error(2,52): PLS-00049: bad bind variable 'NEW.ID'

有什么想法吗？感谢。

Answer 1

似乎错误代码告诉你表格中没有这样的列ID ......

Answer 2

不知何故，您的环境将您的代码视为SQL而不是DDL语句。这对我有用（从命令提示符下运行sqlplus.exe）：

SQL> create sequence mytable_seq;

Sequence created.

SQL> create table mytable (id number);

Table created.

SQL> CREATE OR REPLACE TRIGGER MYTABLE_TRG
  2  BEFORE INSERT ON MYTABLE
  3  FOR EACH ROW
  4  BEGIN
  5   select MYTABLE_SEQ.nextval into :new.id from dual;
  6  END;
  7  /

Trigger created.

请注意尾部的“/” - 这可能在您使用它编译的应用程序中很重要。

Answer 3

如果有人使用适当的命名约定来识别这种类型错误会更容易（正确的意思是使用前缀和后缀）用于更好地暗示其目的的通用对象名称即这样的事情会发现correct答案

  --START -- CREATE A SEQUENCE
  /*
  create table "TBL_NAME" (
     "TBL_NAME_ID"      number(19,0) NOT NULL 
    , ... 
  */  
  --------------------------------------------------------
  --  drop the sequence if it exists
  -- select * from user_sequences ; 
  --------------------------------------------------------
  declare
     c int;
  begin
     select count(*) into c from user_sequences 
      where SEQUENCE_NAME = upper('SEQ_TBL_NAME');
     if c = 1 then
        execute immediate 'DROP SEQUENCE SEQ_TBL_NAME';
     end if;
  end;
  /

  CREATE SEQUENCE  "SEQ_TBL_NAME"  
  MINVALUE 1 MAXVALUE 999999999999999999999999999 
  INCREMENT BY 1 START WITH 1 
  CACHE 20 NOORDER  NOCYCLE ;


  -- CREATE  
  CREATE OR REPLACE TRIGGER "TRG_TBL_NAME" 
  BEFORE INSERT
  ON "TBL_NAME"
  REFERENCING NEW AS New OLD AS Old
  FOR EACH ROW
  DECLARE
  tmpVar NUMBER;

  BEGIN
     tmpVar := 1 ;

     SELECT SEQ_TBL_NAME.NEXTVAL INTO tmpVar FROM dual;
     :NEW.TBL_NAME_ID := tmpVar;

  END TRG_TBL_NAME; 
  /
  ALTER TRIGGER "TRG_TBL_NAME" ENABLE;
  -- STOP  -- CREATE THE TRIGGER

Answer 4

如果您像我一样并且您的代码应该可以工作，请在重新创建触发器之前尝试将其明确删除。愚蠢的甲骨文。

Oracle创建触发器错误（错误的绑定变量）

4 个答案: