Question

我有4个模型：抽屉，文件夹，FolderDocument和Document如下：

class Drawer < ActiveRecord::Base
  has_many :folders #Drawer has many folders
end

class Folder < ActiveRecord::Base
  belongs_to :drawer
  has_many :folder_documents

  # Folder has a "version" attribute which reflects the latest version
  # Use proc to give back latest version by default e.g. folder.documents or folder.documents(5) will give back a specific version.      
  has_many :documents, :through => :folder_documents, :conditions => proc { |v = nil|
         v ||= self.version
         "documents.active IS TRUE AND version = #{v}"
       }, :uniq => true 
end

class FolderDocument < ActiveRecord::Base
  # Has a version attribute
  belongs_to :document
  belongs_to :folder
end

class Document < ActiveRecord::Base
  has_many :folder_documents
  has_many :folders, :through => :folder_documents
end

我的问题是我无法创建

has_many :documents, :through => :folders

在类Drawer上的

作为proc条件（对于FolderDocument中的文档）不能计算为＆＃34;版本＆＃34;在Drawer的上下文中计算，而不是中间文件夹关联。

我是否可以在不在Folder和FolderDocuments之间创建另一个名为FolderVersion的模型的情况下执行此操作？

编辑：目标是获取属于当前版本文件夹的所有文档（文件夹中的版本）。

Rails复杂has_many和has_many通过

0 个答案: