Question

如何在以下代码中修改buffer，然后将更改保存在可执行文件的资源中？我正在寻找像SetString(handle,index,buffer,size)这样的东西。

var
  hExe : Cardinal;
  buffer : array [0..4097] of ansichar;
begin
  hExe:=LoadLibraryEx(PAnsiChar(Edit2.Text),0,LOAD_LIBRARY_AS_DATAFILE);
  LoadString(hExe,65300,buffer,SizeOf(buffer));
  ShowMessage(buffer);
  //need to modify buffer here then I'll unload the resources..
end;

更新：这是我对UpdateResource的尝试

var
  hEXE: DWORD;
  pData: PAnsiChar;
begin
  pData := PAnsiChar(Edit1.Text);
  hEXE := BeginUpdateResource(pchar(edit2.text), FALSE);
  if hEXE <> 0 then
  begin
    UpdateResource(hEXE, RT_string, MAKEINTRESOURCE(4082), LANG_NEUTRAL,
      @pData, Length(pData)); //if i change 4082 to 65300 it creates another key like 4082
    EndUpdateResource(hEXE, FALSE);
  end;

这段代码搞砸了整个4082内容。问题是RT_STRING中名为4082的项是字符串组。当我在资源编辑器中打开exe时，单击字符串表，然后单击4082，结果为：

STRINGTABLE
LANGUAGE LANG_NEUTRAL, SUBLANG_NEUTRAL
{
65296,  "Unicode"
65297,  "Big Endian Unicode"
65298,  "UTF-8"
65299,  "UTF-7"
65300,  "ABCDE12345"
}

所以我需要解析字符串组，或者我需要一个API来设置组中索引为65300的修改字符串。有什么想法吗？

Answer 1

我发现the answer使用了Google。（English translation from Chinese）谢谢大家！

procedure UpdateResString(AFileName, ANewString: string; AStringIdent: Integer);
  procedure WriteToArray(AArray: TByteDynArray; AData: Word; var APos: Integer);
  begin
    AArray[APos] := Lo(AData);
    AArray[APos + 1] := Hi(AData);
    Inc(APos, 2);
  end;

  function ReadFromArray(AArray: TByteDynArray; APos: Integer): Word;
  begin
    Result := AArray[APos] + AArray[APos + 1] * 16;
  end;

var
  hModule, hResInfo, hUpdate: THandle;
  ResData, TempData: TByteDynArray;
  wsNewString: WideString;
  iSection, iIndexInSection: Integer;
  i, iLen, iSkip, iPos: Integer;
begin
  hModule := LoadLibrary(PChar(AFileName));
  if hModule = 0 then
    raise Exception.CreateFmt('file %s failed to load.', [AFileName]);

  // Calculate the resource string area and the string index in that area
  iSection := AStringIdent div 16 + 1;
  iIndexInSection := AStringIdent mod 16;

  // If the resource already exists, then read it out of the original data
  hResInfo := FindResource(hModule, MakeIntResource(iSection), RT_STRING);
  if hResInfo <> 0 then
  begin
    iLen := SizeOfResource(hModule, hResInfo);
    SetLength(ResData, iLen);
    CopyMemory(ResData, LockResource(LoadResource(hModule, hResInfo)), iLen);
  end;
  // Should first close the file, and then update
  FreeLibrary(hModule);
  // Calculate the new data is written to location
  wsNewString := WideString(ANewString);
  iLen := Length(wsNewString);
  iPos := 0;
  for i := 0 to iIndexInSection do
  begin
    if iPos > High(ResData) then
      SetLength(ResData, iPos + 2);
    if i <> iIndexInSection then
    begin
      iSkip := (ReadFromArray(ResData, iPos) + 1) * 2;
      Inc(iPos, iSkip);
    end;
  end;

  // Delete the original data and the data behind the temporary
  // storage of data to be added
  iSkip := (ReadFromArray(ResData, iPos) + 1) * 2;
  TempData := Copy(ResData, iPos + iSkip, Length(ResData) - iSkip);
  SetLength(ResData, iPos);
  SetLength(ResData, iPos + (iLen + 1) * 2 + Length(TempData));

  // Write new data
  WriteToArray(ResData, iLen, iPos);
  for i := 1 to iLen do
    WriteToArray(ResData, Ord(wsNewString[i]), iPos);
  // Write back to the original data
  for i := 0 to High(TempData) do
    ResData[iPos + i] := TempData[i];

  // Write the data back to file
  hUpdate := BeginUpdateResource(PChar(AFileName), False);
  if hUpdate = 0 then
    raise Exception.CreateFmt(
      'cannot write file %s. Please check whether it is open or set read-only.',
      [AFileName]);

  UpdateResource(hUpdate, RT_STRING, MakeIntResource(iSection), LANG_NEUTRAL,
    ResData, Length(ResData));
  EndUpdateResource(hUpdate, False);
end;

Answer 2

您可以看到source code (Delphi 2006)的XN Resource Editor（是一个免费，功能强大，功能齐全的资源编辑器和适用于Windows 98，Windows 2000和Windows XP的PE模块资源管理器）。

此外，您应该检查以下功能

再见。

Answer 3

有一篇文章在Delphi3000上讨论了这个问题：

Resources inside .exe files

Answer 4

我认为您需要使用包含修改的版本替换整个组。这并不难解析，您可以采取一些快捷方式。将所有内容加载到tStringlist中，然后循环列表，直到字符串以'65300'开头。执行替换并将字符串列表的文本部分保存为替换资源。

修改exe资源中的字符串

4 个答案: