Question

我正试图从学生表中获得前5名。表看起来像那样。

   table: student

   id name   score

   1    a     100
   2    b     100
   3    c     90
   4    d     87
   5    e     85
   6    f     88
   7    g     83
   9    h     92

如果我这样做

   select name,score from student order by score desc limit 5

   a    100
   b    100
   h     92
   c     90
   f     88

但是，我希望看到这个结果

我试图找出重复得分为第一有解决方案吗提前谢谢。

Answer 1

SELECT s.*
FROM student AS s
  JOIN
    ( SELECT DISTINCT score
      FROM student
      ORDER BY score DESC
          LIMIT 5
    ) AS lim
    ON s.score = lim.score 
ORDER BY s.score DESC ;

Answer 2

这是一种方式：

select s.*
from student s
where s.score >= (select score
                  from (select distinct score from student order by score desc limit 5) s
                  order by score
                  limit 1
                 )

这会在最内部子查询中按降序获得分数。它将此限制为五个不同的分数。然后，它找到最小值，并返回具有此分数或更高分数的所有行。

Answer 3

尝试使用GROUP BY：

SELECT 
    score
    COUNT(*) AS score_count
FROM 
    student 
GROUP BY
    score
ORDER BY
    score desc 
LIMIT 5

Answer 4

这里是sql fiddle

  SELECT s.id, s.name,s.score FROM tbl_student AS s INNER JOIN (SELECT * FROM tbl_student ORDER BY score DESC LIMIT 0,5) AS s2 ON s2.id=s.id order by s.score desc

我如何在mysql中获得前5名

4 个答案: