我想知道是否有人可以帮我调整我的剧本。
我有我需要的东西,但我只想弄清楚如何使其递归。
e.g。我目前有:
$key = 'XXXXXXXXXXXX';
$sensor = 'false';
$query = 'Place 1';
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?key='.$key.'&query='.urlencode($query).'&sensor='.$sensor;
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$places = curl_exec($ch);
curl_close($ch);
// echo $url;
$output = json_decode($places);
$i = 0;
while ($output->results[$i]->geometry->location->lat != '') {
echo '<strong>' . $query . '</strong><br />';
echo $output->results[$i]->geometry->location->lat . ', '. $output->results[$i]->geometry->location->lng;
echo '<br />' . $output->results[$i]->formatted_address;
echo '<hr />';
$i++;
}
// there is a delay between when the next page token is given and when it is ready to be accessed
sleep(5);
if ($output->next_page_token != '') {
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?pagetoken='.$output->next_page_token.'&key='.$key.'&sensor='.$sensor;
// repeating myself now!
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$places = curl_exec($ch);
curl_close($ch);
$output = json_decode($places);
$i = 0;
while ($output->results[$i]->geometry->location->lat != '') {
echo '<strong>' . $query . '</strong><br />';
echo $output->results[$i]->geometry->location->lat . ', '. $output->results[$i]->geometry->location->lng;
echo '<br />' . $output->results[$i]->formatted_address;
echo '<hr />';
$i++;
}
}
所以,理想情况下,我正在研究如何进行重组,以便只要有下一页令牌,上述内容就会运行。
答案 0 :(得分:2)
至少你可以用if
替换while
。并且可能将while的主体重新分解为函数。
但你不需要递归地调用它,只需迭代地调用它,直到你完成(即不再有下一页令牌)
function doQuery($url)
{
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$places = curl_exec($ch);
curl_close($ch);
$output = json_decode($places);
$i = 0;
while ($output->results[$i]->geometry->location->lat != '') {
echo '<strong>' . $query . '</strong><br />';
echo $output->results[$i]->geometry->location->lat . ', '. $output->results[$i]->geometry->location->lng;
echo '<br />' . $output->results[$i]->formatted_address;
echo '<hr />';
$i++;
}
sleep(5);
return $output->next_page_token;
}
$next_page_token = doQuery($url);
while ($next_page_token != '')
{
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?pagetoken='.$next_page_token.'&key='.$key.'&sensor='.$sensor;
$next_page_token = doQuery($url);
}
答案 1 :(得分:1)
在一个函数中封装你的逻辑,然后在你有下一个页面标记时循环:
function doWorkAndPrint( $url, $query) {
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$places = curl_exec($ch);
curl_close($ch);
$output = json_decode($places);
$i = 0;
while ($output->results[$i]->geometry->location->lat != '') {
echo '<strong>' . $query . '</strong><br />';
echo $output->results[$i]->geometry->location->lat . ', '. $output->results[$i]->geometry->location->lng;
echo '<br />' . $output->results[$i]->formatted_address;
echo '<hr />';
$i++;
}
return $output->next_page_token;
}
现在,你需要循环,而该函数返回一些有用的东西。既然你想要至少做一次,我会使用do ... while
循环:
$key = 'XXXXXXXXXXXX';
$sensor = 'false';
$query = 'Place 1';
do {
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?pagetoken='.$query.'&key='.$key.'&sensor='.$sensor;
$query = doWorkAndPrint( $url, $query);
} while( $query != '');