Question

考虑拥有

的数据库

checkID record_number   data    Order_number
a                0        1        2
a                1        2        0
a                2        3        1
a                3        4        3

查找根据Order_number列获取记录的查询，即过程应该返回数据：

having record _number 2 then
having record _number 0 then
having record _number 1 then
having record _number 3

是否有任何联接或其他查询？

Answer 1

SELECT *
FROM tablename
ORDER BY CASE WHEN record_number = 2 THEN 0 ELSE 1 END, record_number;

SQL Fiddle Demo

这将按以下顺序为您提供数据：

| CHECKID | RECORD_NUMBER | DATA | ORDER_NUMBER |
-------------------------------------------------
|       a |             2 |    3 |            1 |
|       a |             0 |    1 |            2 |
|       a |             1 |    2 |            0 |
|       a |             3 |    4 |            3 |

Answer 2

select  *
from    YourTable
order by
        case record_number
        when 2 then 1
        when 0 then 2
        when 1 then 3
        when 3 then 4
        end

Answer 3

您可以在这种情况下使用 CASE WHEN 。;

SELECT  *
FROM    tbl
ORDER BY CASE record_number
              WHEN 2 THEN 1
              WHEN 0 THEN 2
              WHEN 1 THEN 3
              WHEN 3 THEN 4
              END

这是 SQL Fiddle DEMO 。

| CHECKID | RECORD_NUMBER | DATA | ORDER_NUMBER |
-------------------------------------------------
|       a |             2 |    3 |            1 |
|       a |             0 |    1 |            2 |
|       a |             1 |    2 |            0 |
|       a |             3 |    4 |            3 |

Answer 4

最好的解决方案是创建用于排序检查的附加表，如下所示：

record_number   sort_seq
     2              1
     0              2
     1              3
     3              4

然后将其加入您的表格

select c.* 
from check as c 
     join sortSeq as s on c.record_number=s.record_number 
order by s.sort_seq

Answer 5

SELECT *
FROM tablename
ORDER BY Order_number

基于表中的两列的Sql-排序

5 个答案: