Question

我需要将一个ethereal捕获文件上传到MySQL数据库中。问题是，它不是通过html表单手动完成的。因此，我无法使用enctype="multipart/form-data"和$_FILES上传文件。

有没有办法只使用PHP将文件上传到MySQL数据库。

此致大额牛

Answer 1

Answer 2

“我没有从我的应用程序动态生成的文件，我需要自动上传”

您必须模拟POST请求 - 尝试使用以下示例中的套接字：

<?php    
$filename = 'C:/tmp/myphoto.jpg';
$handler  = 'http://www.example.com/upload.php';
$field    = 'image';
$res = send_file($filename, $handler, $field);


if ($res) {
echo 'done.';
} else {
echo 'something went wrong.';
}
?>



function send_file($fname, $handler, $field)
{
/* check if file exists */
if (!file_exists($fname)) {
    echo 'file not found.';
    return false;
}

/* get file's extension */
preg_match("/\.([^\.]+)$/", $fname, $matches);
$ext = $matches[1];

/* guess mimetype from file's extension 
   please add some more mimetypes here */
switch(strtolower($ext)) {
    case "doc":
        $mime = "application/msword";
        break;
    case "jpeg":
    case "jpg":     
    case "jpe":
        $mime = "image/jpeg";
        break;
    case "gif":
        $mime = "image/gif";
        break;
    case "pdf":
        $mime = "application/pdf";
        break;
    case "png":
        $mime = "image/png";
        break;
    case "txt":
    default:
        $mime = "text/plain";
        break;
}       

/* get hostname and path of remote script */
$host = parse_url($handler, PHP_URL_HOST);
$path = parse_url($handler, PHP_URL_PATH);

/* setup request header and body */
$boundary = "---------" . str_replace(".", "", microtime());
$reqbody  = "--$boundary\r\n"
          . "Content-Disposition: form-data; name=\"$field\"; filename=\"$fname\"\r\n"
          . "Content-Type: $mime\r\n\r\n"
          . file_get_contents($fname) . "\r\n"
          . "--$boundary--\r\n";
$bodylen  = strlen($reqbody);
$reqhead  = "POST $path HTTP/1.1\r\n"
          . "Host: localhost\r\n"
          . "Content-Type: multipart/form-data; boundary=$boundary\r\n"
          . "Content-Length: $bodylen\r\n"
          . "Connection: Close\r\n\r\n";

/* open socket connection to remote host on port 80 */
$fp = fsockopen($host, 80, $errno, $errmsg, 30);

/* check the connection */
if (!$fp) {
    print "Cannot connect to $host!\n";
    return false;
}

/* send request */
fwrite($fp, $reqhead);
fwrite($fp, $reqbody);

/* read response */
$res = "";
while(!feof($fp)) {
    $res .= fgets($fp, 4096);
}       
fclose($fp);

/* separate header and body */
$neck = strpos($res, "\r\n\r\n");
$head = substr($res, 0, $neck);
$body = substr($res, $neck+4);

/* check HTTP status */
$lines = explode("\r\n", $head);
preg_match('/HTTP\/(\\d\\.\\d)\\s*(\\d+)\\s*(.*)/', $lines[0], $m);
$status = $m[2];

if ($status == 200) {
    return(true);
} else {
    return(false);
}
}

Answer 3

你是如何创建文件的？我很确定使用fopen（'yourfilename.txt'，'w'）会创建一个文件（如果没有）。然后你可以将文件名插入你的mysql数据库。

Answer 4

也许就像这样简单;

$data = file_get_contents("yourFile.dat");

然后将'data'变量插入数据库。

我们如何使用php将文件上传到mysql数据库

4 个答案: