Question

我的代码如下：

   #include<stdio.h>
   #include <string.h>
   #include <math.h>
   #include <stdlib.h>
   int string_length(char*);
   void reverse(char*);
   int main(void)
   {
      char num[256];
      printf("%c[%d;%d;%dmPlease enter a number of rows: ", 0x1B, 5, 32, 40);
      gets(num);
      //gets number

printf("%c[%dm\n", 0x1B, 0);
//Resets color

//Variables
char revnum[50], q[50] = "\0", r[50] = "\v";
int i, x, j, z, w;

//Reverses inputted character string
reverse(num);

//Takes reversed inputted character string and out puts it as an integer
for(i = 0; num[i] != '\0'; ++i) {
    j = -(48-num[i]);
    double y = i;
    x = j*pow(10, y) + x;
}

//Takes integer version of inputted character string and assigns a counter's value (counting up to our integer version) to a character string
for (z = 0; z <= x; z++) {
    sprintf(revnum, "%d", z);

    //Takes the new character string for each number up to the inputted value and prints it vertically, but no differentiating between numbers and printing them horizontally to each other
    for (w = 0; revnum[w] != '\0'; ++w) {
        strcat(q, r);
        printf("%s", q);
        strcat(q, revnum[w]);
      }
   }

  }

  //Function which reverses a character string
   void reverse(char *num)
{
int length, c;
char *begin, *end, temp;

length = string_length(num);

begin = num;
end = num;

for ( c = 0 ; c < ( length - 1 ) ; c++ )
    end++;

for ( c = 0 ; c < length/2 ; c++ )
{
    temp = *end;
    *end = *begin;
    *begin = temp;

    begin++;
    end--;
}
}

 int string_length(char *pointer)
 {
int c = 0;

while( *(pointer+c) != '\0' )
    c++;

return c;
}

程序的要点是在输入每个数字垂直的数字之前输出所有数字，然后水平列出数字本身。

请帮助!!!

Answer 1

你犯了几个错误。此代码有效：

#include<stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int string_length(char*);
void reverse(char*);
int main(void)
{
  char num[256];
  printf("Please enter a number of rows: ", 0x1B, 5, 32, 40);
  gets(num);
  //gets number

//Variables
char revnum[50], q[50] = "\0";
int i, x, j, z, w;

//Reverses inputted character string
reverse(num);

//Takes reversed inputted character string and out puts it as an integer
x = atoi(num);

//Takes integer version of inputted character string and assigns a counter's value (counting up to our integer version) to a character string
for (z = 0; z <= x; z++) {
sprintf(revnum, "%d", z);

//Takes the new character string for each number up to the inputted value and prints it vertically, but no differentiating between numbers and printing them horizontally to each other
for (w = 0; revnum[w] != '\0'; ++w) {
    printf("%s\v", q);
char a[2];
sprintf(a,"%c",revnum[w]);
strcat(q,a);
  }
}

}

//Function which reverses a character string
void reverse(char *num)
{
int length, c;
char *begin, *end, temp;

length = string_length(num);

begin = num;
end = num;

for ( c = 0 ; c < ( length - 1 ) ; c++ )
end++;

for ( c = 0 ; c < length/2 ; c++ )
{
temp = *end;
*end = *begin;
*begin = temp;

 begin++;
 end--;
}
}

int string_length(char *pointer)
{
int c = 0;

while( *(pointer+c) != '\0' )
c++;

return c;
}

使用选项 -fno-stack-protector 进行编译，以防止堆栈检测。

strcat和分段错误11

1 个答案: