"Project nr" "Task" "Task deadline" "Task Type Production"
456 packed 1 april 2013 Packed
456 Leave production 3 april 2013 Leave Production
456 Flight date 9 april 2013 Flight Date
123 packed 1 april 2013 Packed
123 Leave production 6 april 2013 Leave Production
123 Flight date 9 april 2013 Flight Date
789 packed 1 april 2013 Packed
789 Leave production 9 april 2013 Leave Production
789 Flight date 9 april 2013 Flight Date
我需要一个如上所示的列表我想在“离开生产”的日期排序项目nr必须像上面的列表一样保持3个小组。
我已经有了这个SQL。该列表正在运行,但排序无效。错误是:无法绑定多部分标识符“task。[task deadline]”。 我如何获得排序?
SELECT [Project nr], Task, TaskDate
FROM (
SELECT MSP_EpmProject_UserView.[Project nr]
,MAX(CASE WHEN [Task Type Production] = 'Packed'
THEN [Task deadline]
END) AS Packed
,MAX(CASE WHEN [Task Type Production] = 'Leave Production'
THEN [Task deadline]
END) AS [Leave Production]
,MAX(CASE WHEN [Task Type Production] = 'Flight Date'
THEN [Task deadline]
END) AS [Flight Date]
FROM MSP_EpmProject_UserView
LEFT JOIN MSP_EpmTask_UserView
ON MSP_EpmProject_UserView.ProjectUID = MSP_EpmTask_UserView.ProjectUID
LEFT JOIN MSP_EpmAssignment_UserView
ON MSP_EpmTask_UserView.TaskUID = MSP_EpmAssignment_UserView.TaskUID
LEFT JOIN MSP_EpmResource_UserView
ON MSP_EpmAssignment_UserView.ResourceUID = MSP_EpmResource_UserView.ResourceUID
WHERE (MSP_EpmTask_UserView.TaskIsProjectSummary = 0)
GROUP BY MSP_EpmProject_UserView.[Project nr]
) data
UNPIVOT
(
TaskDate
for [Task] in ([Pack],[Leave Production],[Flight Date])
) piv
ORDER BY data.[Task deadline]
这是ORDER BY注释掉的结果。我想在上面找到一个没有日期的字段的结果。
Project Nr Task TaskDate
0053 Packed 2013-02-05 17:00:00.000
0053 Leave Production 2011-04-26 17:00:00.000
0053 Flight Date 2011-04-22 17:00:00.000
0071 Leave Production 2011-06-24 17:00:00.000
0081 Leave Production 2012-03-09 17:00:00.000
0081-01 Leave Production 2012-03-09 17:00:00.000
答案 0 :(得分:1)
我假设您的表/视图/ CTE看起来像您问题中的初始表。使用窗口函数获取所有相同“Project nr”的值,然后进行排序:
select "Project nr", "Task", "Task deadline", "Task Type Production"
from (select t.*,
MAX(case when task = 'Leave Production' then "Task deadline" end) over (partition by "Project nr") as lpdl
from t
) t
order by lpdl, 1