Question

使用Ninject DI，我实现了两个我从MVC控制器实例化的接口。例如：

public class MyController : Controller
{
   private readonly IUnitOfWork _UnitOfWork;
   private readonly IAssetService _AssetService;

   public MyController(IUnitOfWork unitOfWork, IAssetService assetService)
   {
      this._UnitOfWork = unitOfWork;
      this._AssetService = assetService;
   }

   // Controller actions etc. 
}

在我的Ninject模块中，我创建了以下绑定：

public class DomainModule : NinjectModule
{
   public override void Load()
   {
      Bind<IUnitOfWork>()
         .To<SqlUnitOfWork>()
         .InRequestScope()
         .WithConstructorArgument("connectionString", "MyDb.Database");

      Bind<IAssetService>()
         .To<FileSystemAssetService>()
         .WithConstructorArgument("rootPath", "C:\\DataStore");
   }
}

我现在想将IUnitOfWork实例注入我的IAssetService，所以我考虑将其设为IAssetService的属性并修改我的控制器，如下所示：

public class MyController : Controller
{
   private readonly IUnitOfWork _UnitOfWork;
   private readonly IAssetService _AssetService;

   public MyController(IUnitOfWork unitOfWork, IAssetService assetService)
   {
      this._UnitOfWork = unitOfWork;
      this._AssetService = assetService;

      this._AssetService.UnitOfWork = this._UnitOfWork;
   }

   // Controller actions etc. 
}

但我想知道是否有更好/更清晰的方法使用不同的DI技术这样做 - 理想情况下我想将IUnitOfWork添加到AssetService构造函数中？

Answer 1

那为什么不简单地将IUnitOfWork注入AssetService？

public class FileSystemAssetService : IAssetService
{
    private readonly IUnitOfWork unitOfWork;
    private readonly string rootPath;

    public FileSystemAssetService(IUnitOfWork unitOfWork, string rootPath)
    {
        this.unitOfWork = unitOfWork;
        this.rootPath = rootPath;
    }
}

引用DI构造函数中的公共实例

1 个答案: