Question

输入：AA1

输出将是：

Char  Count
A     2
1     1

Answer 1

这更容易，因为它只是简单的计数，而不是你的其他问题中的连续性。

DECLARE @Numbers TABLE (Num smallint NOT NULL PRIMARY KEY)

INSERT @Numbers (Num)
SELECT TOP 12
    ROW_NUMBER() OVER (ORDER BY c1.NAME)
FROM
    sys.columns c1

DECLARE @STuff TABLE (Seq char(12) NOT NULL PRIMARY KEY)

INSERT @STuff (Seq) VALUES ('12AABCCDDDDE')
INSERT @STuff (Seq) VALUES ('333345RRRR11')

SELECT
   Seq, Single, COUNT(*)
FROM
   @Numbers N
   CROSS APPLY 
   (SELECT Seq, SUBSTRING(Seq, Num, 1) AS Single FROM @Stuff) S
GROUP BY
   Seq, Single
HAVING
    COUNT(*) > 1
ORDER BY
    Seq, Single

sql server中的字符数

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