所有。 我有一个项目,我需要通过X-Fi声音爆破卡与A / V接收器连接。 A / V接收器连接到7.1扬声器系统。我想知道开始完成单独访问每个7.1通道的方式,以便我可以在模拟器中引导飞机驾驶舱信息。我正在使用OpenAL并在C中编写此代码。我已经开发了一些代码,我认为应该可以解决这个问题,但是我在其他6个扬声器上听到了声音。下面是我已经编写的一些代码的示例。我希望有人能在这里帮助我。
谢谢,文森特。{ ALuint NorthWestSource; ALint PlayStatus;
switch (event)
{
case EVENT_COMMIT:
//Load user selected .wav file into the buffer that is initialized here, "InitBuf".
LoadDotWavFile();
//Generate a source, attach buffer to source, set source position, and play sound.
alGenSources(NumOfSources, &NorthWestSource);
ErrorCheck();
//Attach the buffer that contains the .wav file's data to the source.
alSourcei(NorthWestSource, AL_BUFFER, WavFileDataBuffer);
ErrorCheck();
//Set source's position, velocity, and orientation/direction.
alSourcefv(NorthWestSource, AL_POSITION, SourcePosition);
ErrorCheck();
alSourcefv(NorthWestSource, AL_VELOCITY, SourceVelocity);
ErrorCheck();
alSourcefv(NorthWestSource, AL_DIRECTION, SourceDirectionNorthWest);
ErrorCheck();
alSourcei(NorthWestSource, AL_SOURCE_RELATIVE, AL_TRUE);
ErrorCheck();
alSourcei(NorthWestSource, AL_CONE_INNER_ANGLE, 180);
ErrorCheck();
alSourcei(NorthWestSource, AL_CONE_OUTER_ANGLE, 270);
ErrorCheck();
SetCtrlVal(panelHandle, PANEL_SOURCEISSET, 1);
//Play the user selected file by playing the sources.
alSourcePlay(NorthWestSource);
ErrorCheck();
//Check that the .wav file has finished playing and if so clean things up.
do
{
alGetSourcei(NorthWestSource, AL_SOURCE_STATE, &PlayStatus);
if(PlayStatus != AL_PLAYING)
{
printf("File done playing. \n");
}//End do-while if statement
}
while(PlayStatus == AL_PLAYING);
//Clean things up more before exiting out of this audio projection.
alDeleteSources(NumOfSources, &NorthWestSource);
ErrorCheck();
alDeleteBuffers(NumOfBuffers, &WavFileDataBuffer);
ErrorCheck();
SetCtrlVal(panelHandle, PANEL_SOURCEISSET, 0);
//alDeleteBuffers(NumOfBuffers,
break;
}
return 0;
}`
答案 0 :(得分:0)
我遇到了同样的问题。我想给左耳或右耳发音。到目前为止我找到的唯一方法是用声音为你生成立体声缓冲区(7.1缓冲区),然后用零覆盖另一个通道上的信息(...其他7个通道),然后再播放来自听众面前的来源。
这是我的解决方法。我知道这很笨拙。但是如果你想保持openAL并避免使用ALSA直接编程(对于Linux)或CoreAudio(对于Mac),我没有找到更好的。
更直接地回答你的问题:不,似乎没有直接的说法(正如我所希望的那样):“演讲者#3说'Hello World'!所有其他发言者保持沉默。”
干杯,
法里德