Question

我想使用php将一个大文件卷曲到Hoop。如果我执行正常的php文件上传，那么文件前面会有标题。

当我尝试这个时：

$url = http://hoop:14000/filename?op=create&user.name=root
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_POSTFIELDS, array("file" => "@" . $this->filepath));
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/octet-stream', 'Expect:'));
$content  = curl_exec($ch);

箍上的文件将包含以下标题：

------------------------------f0f063939ed8
Content-Disposition: form-data; name="file"; filename="phpbsA4ty"
Content-Type: application/octet-stream
{binary data here........}

我猜它需要是原始的后期数据。所以我可以这样工作：

    $url = http://hoop:14000/filename?op=create&user.name=root
    $fileData = file_get_contents($this->filepath);

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, TRUE);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, TRUE);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $fileData);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/octet-stream', 'Expect:'));
    $content  = curl_exec($ch);

但是大文件会导致内存错误：

PHP Fatal error:  Allowed memory size of 33554432 bytes exhausted (tried to allocate 8388608 bytes)

有没有办法在不将文件加载到内存的情况下发布原始文件？

我可以使用Hoop文档中的说明在命令行上执行此操作

curl -X POST -c ~/.hoopauth "http://<HOOP_HOST>:14000/<PATH>?op=create[&<OPTION>]*" \ --data-binary @data.txt  --header "content-type: application/octet-stream"

这 http://cloudera.github.com/hoop/docs/latest/HttpRestApi.html

如何使用PHP通过Hoop将文件卷曲到hadoop

0 个答案: