# Lists.
months = [6, 2, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4]
weekdays = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
# Functions for algorithm.
def yearcode(y):
"""generate year-code using algorithm"""
y = y % 100
y = y + (y / 4) % 7
return round(y)
def monthcode(m):
"""get month number from month-list"""
return months[monthin - 1]
def daycode(d):
"""simplify day number for efficiency"""
return d % 7
# Inputs.
dayayin = int(input("What Day in the Month?"))
monthin = int(input("What Month? E.g.- January is 1"))
yearin = int(input("What Year?"))
# Define variables for functions.
yearout = yearcode(yearin)
monthout = monthcode(monthin)
dayout = daycode(dayin)
# Final Add-Up and Output.
result = (dayout + monthout + yearout) % 7
print(weekdays[result])
错误是：“ParseError：第17行的错误输入”此程序的目的是给出任何日期的星期几。正如你所看到的那样，我对为了我的利益而给出功能的目的并不满意。我真的觉得我在这里错过了一些东西。
以下是改进版和工作版（感谢您的帮助！）
# Lists.
months = [6, 2, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4]
weekdays = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
# Fruitful Functions for Algorithm.
def yearcode(y):
"""Year Code Generator Algorithm"""
y = y % 100
y = y + (y / 4) % 7
return int(round(y))
def monthcode(m):
"""Retrieve Month Number from Month List"""
return months[m - 1]
def daycode(d):
"""Simplify Day Input for Efficiency"""
return d % 7
# Inputs.
dayin = int(input("What Day in the Month?"))
monthin = int(input("What Month? E.g.- January is 1"))
yearin = int(input("What Year?"))
# Define Variables for Functions.
yearout = yearcode(yearin)
monthout = monthcode(monthin)
dayout = daycode(dayin)
# Final Add-Up and Output.
result = int((dayout + monthout + yearout) % 7)
print(weekdays[result])
答案 0 :(得分：4)
由于混合空格和标签的问题，您可能会收到错误。尝试使用
运行脚本python -t yourscript.py
看看它是否告诉你任何事情。
也许，在calendar模块中使用内置函数会更容易。
>>> import calendar
>>> calendar.weekday(2013,2,18)
0
>>> calendar.day_name[calendar.weekday(2013,2,18)]
'Monday'
作为旁注，运行代码，我没有得到ParseError - 我得到NameError因为dayin未定义。也许你不是故意将它命名为dayayin？
答案 1 :(得分：1)
你应该在月份代码功能的主体中使用“m”而不是“monthin”
答案 2 :(得分：1)
我已经看到一些简单的错误：
可能是使用变量dayayin而不是dayin
dayayin = int(input("What Day in the Month?"))
...
dayout = daycode(dayin)
在函数monthcode中，mothin来自何处？
def monthcode(m):
"""get month number from month-list"""
return months[monthin - 1]
修改
修复这些后，并使result为整数
result = int((dayout + monthout + yearout) % 7)
脚本运行，但代码中仍有一些错误。当我输入我的出生日期（1978年5月19日）时，它将在周四返回，但我出生在星期五。
答案 3 :(得分：1)
我同意BioGeek
脚本运行，但你的内容仍有一些错误 码。当我输入我的出生日期（1978年5月19日）时，它将在周四返回， 但我出生在星期五。
与多个在线计算器相比，您的工作版似乎有一天休息。 e.g。
What Day in the Month?19
What Month? E.g.- January is 15
What Year?1942
Monday
但其他计算器将其显示为Tuesday。
答案 4 :(得分：0)
您是否尝试删除该行并手动重新输入？我经常看到人们，特别是Mac用户，输入不可见的Unicode字符（alt +空格，如果我没记错的话）。这可能是您问题的根源。
答案 5 :(得分：0)
正如我在其他答案中所说，当我进入出生日期时，它给出了错误的答案。
更具体地说，当您在2013年尝试某个日期时，您的代码会给出正确的答案，但是一旦您尝试将其用于更晚或将来的日期，其返回错误的概率为81.76％回答。其中，它没有考虑到闰年，也没有补偿21世纪以外的日期。
试图找出出错的地方我需要知道你使用的是哪种算法。列表[6, 2, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4]的Googeling让我找到了this page（pdf），其中有一个非常详细的描述，但是您的算法中还有一些额外的步骤。
所以这是我对该算法的实现。我根据mgilson提供的calendar解决方案检查了自公历开始至2300年的每个日期。
import datetime
import calendar
months = [6, 2, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4]
weekdays = ["Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday", "Sunday"]
centuries = {17: 5,
18: 3,
19: 1,
20: 0,
21: -2,
22: -4}
def day_of_week_biogeek(day, month, year):
# This algorithm is only valid for the Gregorian calendar
# which began on September 14, 1752.
if year <= 1752 and month <= 9 and day < 14:
raise RuntimeError("This algorithm is only valid for the Gregorian " + \
"calendar which began on September 14, 1752.")
if year >= 2300:
raise RuntimeError("This algorithm is only valid for the Gregorian " + \
"calendar up till December 31, 2299.")
# Take multiples of 28 from the the last 2 digits of the year
y = divmod(year, 100)[1] % 28
# Add a quarter of the nearest multiple of 4 below the number,
y += divmod(y, 4)[0]
# Take away 7 or multiples of 7. This leaves us the year code
y = y % 7
# The code for the month from the table above
m = months[month - 1]
# If it is a leap year AND the month is January or February, subtract 1
if is_leap_year(year) and month in [1,2]:
m -= 1
# Take away 7 or multiples of 7 from the day
d = day % 7
# Add the codes for the year, the month and the day
result = y + m + d
# Add 1 if the date is in the 1900s
result += centuries[divmod(year, 100)[0]]
# Take away 7 or multiples of 7
result = result % 7
# The final number indicates day of the week
return weekdays[result]
def is_leap_year(year):
# Leap years are the years evenly divisible by 4
# unless it ends in 00 and is a multiple of 400
if not year % 400:
return True
elif not year % 100:
return False
elif not year % 4:
return True
return False
# original code by user2080262
def yearcode(y):
"""Year Code Generator Algorithm"""
y = y % 100
y = y + (y / 4) % 7
return int(round(y))
def monthcode(m):
"""Retrieve Month Number from Month List"""
return months[m - 1]
def daycode(d):
"""Simplify Day Input for Efficiency"""
return d % 7
def day_of_week_user2080262(dayin, monthin, yearin):
yearout = yearcode(yearin)
monthout = monthcode(monthin)
dayout = daycode(dayin)
result = int((dayout + monthout + yearout) % 7)
return weekdays[result]
# alternate solution using builtin functions
def day_of_week_mgilson(day, month, year):
""" See https://stackoverflow.com/a/14941764/50065"""
c = calendar.weekday(year, month, day)
return calendar.day_name[c]
def date_generator(day, month, year):
"""Convience function to return the next day"""
d = datetime.date(year, month, day)
while True:
d += datetime.timedelta(days=1)
yield d.day, d.month, d.year
if __name__ == '__main__':
# checking all days from the beginning of the Gregorian
# calender till 2300
methods = {'user2080262': day_of_week_user2080262,
'BioGeek': day_of_week_biogeek}
for user, func in methods.items():
checked = 0
wrong = 0
d = date_generator(14, 9, 1752)
for day, month, year in d:
checked += 1
if year == 2300:
break
if func(day, month, year) != day_of_week_mgilson(day, month, year):
wrong += 1
print("The code by {0} gives a wrong answer ".format(user) + \
"{0:.2f}% of the time.".format((float(wrong)/checked)*100))