Question

private static string SetValue(string input, string reference)
{
    string[] sentence = input.Split(' ');
    for(int word = 0; word<sentence.Length; word++)
    {
        if (sentence[word].Equals(reference, StringComparison.OrdinalIgnoreCase))
        {
            return String.Join(" ", sentence.subarray(word+1,sentence.Length))
        }
    }
}

如何轻松完成sentence.subarray(word+1,sentence.Length)或以其他方式执行此操作？

Answer 1

String.Join专门针对此an overload：

return String.Join(" ", sentence, word + 1, sentence.Length - (word + 1));

Answer 2

如果您正在寻找独立于string.Join（）函数的Subarray解决方案，并且您正在使用支持Linq的.NET版本，那么我可以推荐：

sentence.Skip(word + 1);

Answer 3

您可以对index使用重载Where：

return string.Join(" ", sentence.Where((w, i) => i > word));

Answer 4

或者，您可以使用SkipWhile代替for循环。

private static string SetValue(string input, string reference)
{
    var sentence = input.Split(" ");
    // Skip up to the reference (but not the reference itself)
    var rest = sentence.SkipWhile( 
        s => !s.Equals(reference, StringComparison.OrdinalIgnoreCase));
    rest = rest.Skip(1); // Skip the reference
    return string.Join(" ", rest);
}

加入其余的字符串数组

4 个答案: