我想创建一个具有给定初始资本和固定年度百分比率(利息)的循环,该循环打印出当前年度的当前资本,直至并包括资本加倍的年份。
例如,初始资本为3000,利息为12。//3000*(1 + 12 / 100) = 3360
output
year 1 = 3360
year 2 = 3763.2
year 3 = 4214.78
year 4 = 4720.55
year 5 = 5287,02
year 6 = 5921,46
//end (when the initial capital(3000) has doubled (6000))
我需要帮助的是创建一个循环,它将计算并显示输出,直到资本加倍使用for循环或while循环。输出不必像示例那样类似。
这是我到目前为止创建的代码:
double initialcapital = 0;
double interest = 0;
int year = 0;
double capital = 0;
Console.Write("Initial capital: ");
initialcapital = int.Parse(Console.ReadLine());
Console.Write("Interest: ");
interest = int.Parse(Console.ReadLine());
capital = initialcapital * (1 + interest / 100);
year = year + 1
Console.Writeline(capital);
答案 0 :(得分:1)
void displayCapital(double initalcapital, double interest){
int year = 1;
double capital = initialcapital;
while(initialcapital > capital / 2) {
Console.Write("Initial capital: ");
initialcapital = int.Parse(Console.ReadLine());
Console.Write("Interest: ");
interest = int.Parse(Console.ReadLine());
capital = initialcapital * (1 + interest / 100);
year = year + 1
Console.Writeline(capital);
}
}
只需调用displayCapital(3000,12);你已经完成了
答案 1 :(得分:1)
如果您想在金额加倍之前找到确切的年数,可以使用:
double exactYears = Math.Log(2) / Math.Log((100 + interest) / 100);
否则以下内容适用于您:
double initialCapital = 0;
double interest = 0;
int year = 0;
double capital = 0;
Console.Write("Initial capital: ");
initialCapital = int.Parse(Console.ReadLine());
Console.Write("Interest: ");
interest = int.Parse(Console.ReadLine());
capital = initialCapital;
while (capital < initialCapital * 2)
{
capital = capital * (1 + interest / 100);
year = year + 1;
Console.WriteLine("Years: " + year);
Console.WriteLine("Capital: " + capital);
}
Console.WriteLine("Years: " + year);
Console.WriteLine("Capital: " + capital);
double exactYears = Math.Log(2) / Math.Log((100 + interest) / 100);
Console.WriteLine(string.Format("Capital doubled in exactly: {0:0.000} years", exactYears));