Question

我不知道如何处理$ .post（）上的404错误

$.post(url, data, function(returnedData) {

它只能处理成功数据，但我也想处理404错误。我知道如何用ajax做但不知道用这个函数请帮忙。

    function returnData(url,data,type){
        $.post(url, data, function(returnedData) {
        if(type == "contacts")
        {   
        ko.applyBindings(new ContactsViewModel(returnedData,"#KnockOutContacts",url,data),$("#KnockOutContacts")[0]);   
        ko.applyBindings(new ContactsViewModel(returnedData,"#ContactDetails",url,data),$("#ContactDetails")[0]);   
        }
        else if(type == "logs")
        {
        alert(returnedData);
        alert(1);
        ko.applyBindings(new LogsViewModel(returnedData,url,data),$("#KnockOutLogs")[0]);   
        }
        else if(type == "sms")
        {
            ko.applyBindings(new SmsViewModel(returnedData,"#KnockOutSmsData",url,data),$("#KnockOutSmsData")[0]);  
            ko.applyBindings(new SmsViewModel(returnedData,"#KnockOutSms",url,data),$("#KnockOutSms")[0]);  
        }
        else if(type == "calendar")
        {
        ko.applyBindings(new CalendarViewModel(returnedData,"#KnockOutCalendar",url,data),$("#KnockOutCalendar")[0]);   
        }
        else if(type == "search")
        {
        ko.applyBindings(new SearchViewModel(returnedData,"#searchbox",url,data),$("#searchbox")[0]);   
        }
        else if(type == "location")
        {
        ko.applyBindings(new LocationViewModel(returnedData,"#KnockOutMaps",url,data),$("#KnockOutMaps")[0]);   
        }
        else if(type == "photos")
        {
        ko.applyBindings(new PhotosViewModel(returnedData,"#photogallary",url,data),$("#photogallary")[0]); 
        ko.applyBindings(new PhotosViewModel(returnedData,"#PhotosDown",url,data),$("#PhotosDown")[0]); 
        }
    });
}

我在获取数据时基本上应用绑定但是当我没有获取数据时它不会进入成功函数并且这会破坏我的js。

Answer 1

了解statusCode回调here

$.ajax({
    url: "/page.htm",
    type: "POST",
    statusCode: {
        404: function() {
          alert("page not found");
        }
    }
})

编辑。

也可以获得$.post

$.post(url, data, function(returnedData) {
    //callback
}).fail(function(jqXHR, textStatus, errorThrown){
    if(jqXHR.status == 404) {

    }
});

Answer 2

您可以使用全局错误处理程序：

$(document).ajaxError(function(e, xhr, settings, exception) {

});

如何在jquery.post中处理404错误

2 个答案: