Question

我的JSON如下：

"message_defaults": {
      "LabResultsRequestDefaultMessage": {
        "MsgTypeId": 8,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Lab Department"
      },
      "ReferralRequestDefaultMessage": {
        "MsgTypeId": 6,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Physican"
      },
      "MessageComposeDefaultMessage": {
        "MsgTypeId": 1,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Office Manager/Willis Sam"
      }
}

现在message_defaluts中的每个elemet都具有相同的结构（假设一个名为MessageDefault.java的POJO）。那么如何将所有message defaults作为List<MessageDefault> ??

我正在使用gson进行解析。此外，我无法更改JSON响应。

编辑::

MessageDefault.java

public class MessageDefault{
    private String defaultMessage;
    private String firstName;
    private String lastName;
    private String mI;
    private int msgTypeId;
    private int staffId;
    private String staffName;

    public String getDefaultMessage(){
        return this.defaultMessage;
    }
    public void setDefaultMessage(String defaultMessage){
        this.defaultMessage = defaultMessage;
    }
    public String getFirstName(){
        return this.firstName;
    }
    public void setFirstName(String firstName){
        this.firstName = firstName;
    }
    public String getLastName(){
        return this.lastName;
    }
    public void setLastName(String lastName){
        this.lastName = lastName;
    }
    public String getMI(){
        return this.mI;
    }
    public void setMI(String mI){
        this.mI = mI;
    }
    public int getMsgTypeId(){
        return this.msgTypeId;
    }
    public void setMsgTypeId(int msgTypeId){
        this.msgTypeId = msgTypeId;
    }
    public int getStaffId(){
        return this.staffId;
    }
    public void setStaffId(int staffId){
        this.staffId = staffId;
    }
    public String getStaffName(){
        return this.staffName;
    }
    public void setStaffName(String staffName){
        this.staffName = staffName;
    }
}

它只是所有message_defualts的结构。但是在JSON中，message_defualts的每个子节点都有不同的名称，如LabResultsRequestDefaultMessage, ReferralRequestDefaultMessage etc，它们反映在POJO MessageDefault.java中。但是从JSON我想要它们的列表。

感谢。

Answer 1

如果你想首先从json获取List，你必须更正你的json。列表必须在'[]'中。

"message_defaults": [{
      "LabResultsRequestDefaultMessage": {
        "MsgTypeId": 8,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Lab Department"
      },
      "ReferralRequestDefaultMessage": {
        "MsgTypeId": 6,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Physican"
      },
      "MessageComposeDefaultMessage": {
        "MsgTypeId": 1,
        "StaffId": 122,
        "StaffName": "Willis,Sam",
        "FirstName": "Sam",
        "MI": "D",
        "LastName": "Willis",
        "DefaultMessage": "Office Manager/Willis Sam"
      }
}]

编辑：尝试将其转换为列表

Type collectionType = new TypeToken<Collection<Integer>>(){}.getType();
Collection<Integer> ints2 = gson.fromJson(json, collectionType);

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Answer 2

您可以在不更改json结构的情况下执行以下操作。

Type mapType = new TypeToken<Map<String, MessageDefault>>() {}.getType();
Map<String, MessageDefault> messagesMap = gson.fromJson(json, mapType);
List<MessageDefault> messages = new ArrayList<MessageDefault>(messagesMap.values());

使用GSON将JSON解析为POJO

2 个答案: