针对LinkedIn API的OAuth不断返回401.导致此问题的原因是什么?

时间:2013-02-18 03:04:52

标签: ios api oauth linkedin afnetworking

我正在使用AFNetworking,AFOAuth1Client和AFLinkedInOAuth1Client从LinkedIn的API获取OAuth令牌。这一切都运作良好。

当我使用getPath拨打电话v1/people/~时,我一直在收到401。

如果我将所有相同的值从我的代码推送到LinkedIn控制台,生成的链接将为我提供我所依赖的基本配置文件。

造成401的原因是什么?我感觉它是AFNetworking或我的配置。

另外,您对如何诊断潜在问题有什么建议吗?

以下代码

+ (JJLinkedInClient *)sharedInstance {
    DEFINE_SHARED_INSTANCE_USING_BLOCK(^{
        return [[self alloc] init];
    });
}

- (id)init {

    if ( (self = [super init]) ) {
        _client = [[AFLinkedInOAuth1Client alloc] initWithBaseURL:[NSURL URLWithString:kJJLinkedInAPIBaseURLString]
                                                              key:@"XXXXXXXX"
                                                           secret:@"YYYYYYYY"];

//        [_client registerHTTPOperationClass:[AFJSONRequestOperation class]];
        [_client registerHTTPOperationClass:[AFHTTPRequestOperation class]];
//        [_client setDefaultHeader:@"Accept" value:@"application/json"];
    }

    return self;
}

- (void)authorize:(void(^)())success {

    __block JJLinkedInClient *weakSelf = self;

    [self.client authorizeUsingOAuthWithRequestTokenPath:@"uas/oauth/requestToken"
                                      userAuthorizationPath:@"uas/oauth/authorize"
                                                callbackURL:[NSURL URLWithString:@"XXXXXXX://linkedin-auth-success"]
                                            accessTokenPath:@"uas/oauth/accessToken"
                                               accessMethod:@"POST"
                                                    success:^(AFOAuth1Token *accessToken) {
                                                        NSLog(@"Success: %@", accessToken);
                                                        [weakSelf getProfile];
                                                        success();
                                                    } failure:^(NSError *error) {
                                                        NSLog(@"Error: %@", error);
                                                    }];
}

- (void)getProfile {

    [self.client getPath:@"v1/people/~"
              parameters:nil
                 success:^(AFHTTPRequestOperation *operation, id responseObject) {
                     NSLog(@"%@", responseObject);
                 }
                 failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                     NSLog(@"%@", error);
                 }];    
}

1 个答案:

答案 0 :(得分:2)

问题出在AFOAuth1Client内的AFPercentEscapedQueryStringPairMemberFromStringWithEncoding函数中。它不需要逃脱波浪号,它需要逃避逗号。

因为这是一个静态函数,我不认为我可以在AFLinkedInOAuth1Client中覆盖它。我将跟进@mattt并看看他说的话。现在您可以将其更改为此,以使其正常工作:

static NSString * AFPercentEscapedQueryStringPairMemberFromStringWithEncoding(NSString *string, NSStringEncoding encoding) {
    static NSString * const kAFCharactersToBeEscaped = @":/?&=;+!@#$(),";
    static NSString * const kAFCharactersToLeaveUnescaped = @"[].~";
//    static NSString * const kAFCharactersToBeEscaped = @":/?&=;+!@#$()~";
//    static NSString * const kAFCharactersToLeaveUnescaped = @"[].";

    return (__bridge_transfer  NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (__bridge CFStringRef)string, (__bridge CFStringRef)kAFCharactersToLeaveUnescaped, (__bridge CFStringRef)kAFCharactersToBeEscaped, CFStringConvertNSStringEncodingToEncoding(encoding));
}