如果/ include，在PHP内部编写PHP路径+ url扩展名

Question

使用Wordpress并希望在此代码中使用PHP函数

<?php if ( is_page(19074) ) { 
include("/home/something/public_html/wp-content/themes/mytheme/folder/page1.html");
} 
elseif ( is_page(18956) ) { 
include("home/something/public_html/wp-content/themes/mytheme/folder/page2.html");
}  
elseif ( is_page(19082) ) { 
include("home/something/public_html/wp-content/themes/mytheme/folder/page3.html");
} 
else {
include("home/something/public_html/wp-content/themes/mytheme/folder/page4.html"); }?>

我不想在这里使用Wordpress PHP函数get_template_directory（）就像我会这样做

<?php get_template_directory(); ?>/folder/page1.html

一直在尝试一些不同的解决方案，但PHP不是我最强的区域，所以一点帮助就太棒了。

Answer 1

include(get_template_directory() . "/folder/page1.html");

OR

最好将它存储在变量中，以免造成很多次调用函数的开销。

$temp_dir = get_template_directory() ;
include($temp_dir . "/folder/page1.html");
include($temp_dir . "/folder/page2.html");
include($temp_dir . "/folder/page3.html");
include($temp_dir . "/folder/page4.html");

希望它有所帮助。