我遇到了将实体保存回给我这个错误的问题:
Catchable Fatal Error: Method My\BusinessBundle\Entity\Type::__toString()
must return a string value in
/var/www/MyBusiness0_1/vendor/doctrine/orm/lib/Doctrine/ORM/ORMInvalidArgumentException.php line 113
奇怪的是方法__ toString()是实体Type!
class Type
{
//..
/**
* @var string
*
* @ORM\Column(name="type", type="string", length=100)
*/
private $type;
/**
* @ORM\OneToMany(targetEntity="MailTelCont", mappedBy="type")
*/
protected $mailTelContacts;
public function __construct()
{
$this->mailTelContacts = new \Doctrine\Common\Collections\ArrayCollection();
}
public function __toString()
{
return $this->getType();
}
//...
另一个奇怪的事情是,如果我在ManyToOne上放置cascade = {“persist”}类MailTelCont“type”并没有向我显示此错误,而是在Type中保存一个新字段..
类MailTelCont
class MailTelCont
{
//..
/**
* @var string
*
* @ORM\Column(name="contact", type="string", length=100)
*/
private $contact;
/**
* @ORM\ManyToOne(targetEntity="Type", inversedBy="mailTelContacts")
* @ORM\JoinColumn(name="type_id", referencedColumnName="id")
*/
private $type;
/**
* @ORM\ManyToOne(targetEntity="Anagrafica", inversedBy="mailTelContacts", cascade={"persist"})
* @ORM\JoinColumn(name="anagrafica_id", referencedColumnName="id")
* @Assert\Type(type="My\BusinessBundle\Entity\Anagrafica")
*/
private $anagrafica;
public function __toString()
{
return $this->getContact();
}
以这种方式调用嵌套的“AnagraficType”形式:
class TypeType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('type', 'entity', array(
'class' => 'My\BusinessBundle\Entity\Type',
'attr' => array('class' => 'conct'),
'property' => 'type',
'label' => 'Tipologia',
))
;
}
*****
class MailTelContType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('type', new TypeType())
->add('contact', 'text', array('label' => 'Contatto'))
;
}
*****
class AnagraficaType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('mailTelContacts', 'collection', array('type' => new MailTelContType(),
'allow_add' => true,
'allow_delete' => true,
'prototype' => true,
'by_reference' => false
))
我在哪里做错了?
答案 0 :(得分:13)
我认为这些值是null
。你试过了吗?
public function __toString()
{
return (string) $this->getType();
}
和
public function __toString()
{
return (string) $this->getContact();
}
当值为null
时,这种方法将被转换为字符串,您不应该得到此异常。