如何找到指定日期四分之一的开始日期和名称(1,2,3等)?
答案 0 :(得分:103)
像(未经测试)的东西:
DateTime date;
int quarterNumber = (date.Month-1)/3+1;
DateTime firstDayOfQuarter = new DateTime(date.Year, (quarterNumber-1)*3+1,1);
DateTime lastDayOfQuarter = firstDayOfQuarter.AddMonths(3).AddDays(-1);
答案 1 :(得分:5)
int GetQuarterName(DateTime myDate)
{
return (int)Math.Ceiling(myDate.Month / 3.0);
}
DateTime GetQuarterStartingDate(DateTime myDate)
{
return new DateTime(myDate.Year,(3*GetQuarterName(myDate))-2,1);
}
GetQuarterName
获取当前月份数/ 3的“下一个”整数值。
GetQuarterStartingDate
使用GetQuarterName
的输出计算月份值,原始日期的年份部分,以及1表示要返回的月份的第一天。
(道歉没有意义,我有流感。:()
答案 2 :(得分:2)
https://msdn.microsoft.com/ru-ru/library/ms127415(v=vs.110).aspx
using Microsoft.VisualBasic;
var quarter = DateAndTime.DatePart(DateInterval.Quarter, (DateTime)dateTimePickerDateTime.Value);
答案 3 :(得分:0)
更简单的两个班轮,带有现场演示 here +按 F8 即可运行。
var date = DateTime.Now; //Give you own DateTime
int offset = 2, monthsInQtr = 3;
var quarter = (date.Month + offset) / monthsInQtr; //To find which quarter
var totalMonths = quarter * monthsInQtr;
var startDateInQtr = new DateTime(date.Year, totalMonths - offset, 1); //start date in quarter
如果您正在查看本季度的最后一天,请使用 DateTime.DaysInMonth
var endDateInQtr = new DateTime(date.Year, totalMonths, DateTime.DaysInMonth(date.Year, totalMonths));
答案 4 :(得分:0)
我认为此解决方案会很好地工作。它占用更多的线路,总线非常冗长! `
private DateTime GetFirstDayOfYearlyQuarter(DateTime value)
{
switch (value.Month)
{
case 1:
case 2:
case 3:
return new DateTime(value.Year, 1, 1);
case 4:
case 5:
case 6:
return new DateTime(value.Year, 4, 1);
case 7:
case 8:
case 9:
return new DateTime(value.Year, 7, 1);
case 10:
case 11:
case 12:
return new DateTime(value.Year, 10, 1);
default:
throw new Exception(@"¯\_(ツ)_/¯");
}
}
`
P.S。这只会找到季度的第一天,但是您可以轻松地将其扩展为季度的数量,等等。
答案 5 :(得分:0)
public static class DateTimeExtensions
{
public static DateTime StartOfQuarter(this DateTime _date)
{
var quarter = decimal.ToInt16(Math.Ceiling(_date.Month / 3.0m));
return new DateTime(_date.Year, quarter, 1);
}
}
使用
var quarterStart = DateTime.Today.StartOfQuarter();
答案 6 :(得分:0)
DateTime date;
int quarterNumber = (date.Month-1)/3+1;
DateTime firstDayOfQuarter = new DateTime(date.Year, (quarterNumber-1)*3+1,1);
DateTime lastDayOfQuarter = firstDayOfQuarter.AddMonths(3).AddDays(-1);