Question

在下面的代码中，我想在结构中包含第三个维度。已经定义了结构基因型和其余标识符。这没有问题：

struct genotype ** populationrows = (struct genotype **) calloc(MAXGENS, sizeof(struct genotype *));

  for (k=0; k< MAXGENS; k++) {

    populationrows[k]= (struct genotype *) calloc (POPSIZE, sizeof (struct genotype));  

    for (j=0; j<2; j++) {
      for (i=0; i<3; i++) { 
        populationrows[k][j].fitness = 0;
        populationrows[k][j].rfitness = 0;
        populationrows[k][j].cfitness = 0;
        populationrows[k][j].lower[i] = 1.0;
        populationrows[k][j].upper[i]= 2.0;
        populationrows[k][j].gene[i] = 3.0;
        printf(" populationrows[%u][%u].gene[%u]=%25lf \n", k,j,i,populationrows[k][j].gene[i]); 
      }
    }   
  }

对于第三维，我尝试了以下内容：

struct genotype * ** populationrows =（struct genotype * **）calloc（numFiles，sizeof（struct genotype * *））;

for（w = 0; w＆lt; numFiles; w ++）{

populationrows [w] =（struct genotype **）calloc（MAXGENS，sizeof（struct genotype *））;

for (k=0; k<MAXGENS; k++) {    
  for (j=0; j<2; j++) {
    for (i=0; i<3; i++) {   
      populationrows[w][k][j].fitness = 0;
      populationrows[w][k][j].rfitness = 0;
      populationrows[w][k][j].cfitness = 0;
      populationrows[w][k][j].lower[i] = 1.0;
      populationrows[w][k][j].upper[i]= 2.0;
      populationrows[w][k][j].gene[i] = 3.0;
      printf(" populationrows[%u][%u][%u].gene[%u]=%25lf \n", w,k,j,i,populationrows[w][k][j].gene[i]); 
    }
  }     
 }  
}

但是这给了我一个分段错误。

你介意告诉我如何避免这种分段错误吗？任何帮助将非常感谢。

提前感谢您的回复!!!

Answer 1

我假设它是C。

而不是指向数据指针的指针数组更好地使用平面数组。这样的事情：

int n_w = 42, n_k = 23, n_j = 423; // size of dimensions

struct genotype * population = (struct genotype *) calloc(n_w * n_k * n_j, sizeof(struct genotype));

你得到了元素（10,11,12），然后是：

population[10 * n_k * n_j + 11 * n_j + 12].fitness = 0;

如果你把它放到函数中，它会变得漂亮：

int n_w = 42, n_k = 23, n_j = 423; // size of dimensions

struct genotype * create_array() {
    return (struct genotype *) calloc(n_w * n_k * n_j, sizeof(struct genotype));
}

struct genotype * get_element(int w, int k, int j) {
    return &population[w * n_k * n_j + k * n_j + j];
}

// ...

struct genotype * population = create_array();

get_element(10, 11, 12)->fitness = 0;

三维结构的内存分配

1 个答案: