访问结构中结构中的指针

Question

引发错误，我不确定原因：

  

physics.c：74：错误：初始化中不兼容的类型

typedef struct gameBody gameBody;

struct gameBody
{
    cpBody *body;
    int numberOfShapes;
    cpShape *arrayOfShapes; //This stores an array of pointers to Shapes
};

//Struct that stores the cpSpace object and the array of pointers to the body objects
typedef struct gameSpace gameSpace;

struct gameSpace
{ 
    cpSpace *space;
    int numberOfObjects;
    gameBody *arrayOfObjects;       //This stores an array of gameBodys
};


for(int i = 0; i < space -> numberOfObjects; i++)
{
    //body info
    gameBody *gBody = space -> arrayOfObjects[i];
}

Answer 1

我猜它在行

gameBody *gBody = space -> arrayOfObjects[i];

虽然space->arrayOfObject是指针，但space->arrayOfObject[i] 不是指针。

您必须声明gBody不是指针：

gameBody gBody = space->arrayOfObjects[i];

或者在数组中的对象上使用address-of运算符;

gameBody *gBody = &space->arrayOfObjects[i];

Answer 2

试

 gameBody *gBody = &(space -> arrayOfObjects[i]);

或

gameBody *gBody = space -> arrayOfObjects + i;

Answer 3

gBody的类型为gameBody *，space->arrayOfObjects[i]的类型为gamebody。也许你想要：

gameBody *gBody = &space->arrayOfObjects[i];

Answer 4

来自您发布的代码

gameBody *gBody = space->arrayOfObjects[i]＆lt;〜是问题......

应该是：

gameBody *gBody = &(space->arrayOfObjects[i]);