请原谅我,如果问题听起来很愚蠢 - 我刚刚开始使用Executor。
我有一个以这种方式使用线程的现有Java应用程序 - 基本上使用独立线程 -
private Thread spawnThread( )
{
Thread t = new Thread()
{
String taskSnap = task.toString();
public void run()
{
try
{
println( task.run( null ) );
}catch( InterruptedException e )
{
println( "ITC - " + taskSnap + " interrupted " );
}
}
};
return t;
}
从上面可以看出,该函数返回一个新线程。
现在在程序的main()函数中,以这种方式创建一个新线程 -
taskThread = spawnThread();
taskThread.start();
我想要做的是,创建一个执行者服务(具有固定数量的线程) - >然后通过新线程将创建新线程/执行任务交给该执行者。
由于我是Executor的新手,我想知道的是,如何更改上面的代码,以便在线程池中创建新的线程而不是形成新的单独线程。我看不到任何创建线程的命令(在线程池中) - >将上述任务交给该线程(而不是如上所述的独立线程)。
请告诉我如何解决此问题。
答案 0 :(得分:9)
在你的主体中,你可以这样写:
ExecutorService executor = Executors.newFixedThreadPool(nThreads);
executor.submit(new Runnable() {
String taskSnap = task.toString();
public void run() {
try {
println(task.run(null));
} catch( InterruptedException e) {
println("ITC - " + taskSnap + " interrupted ");
}
}
});
submit方法将在executor服务中的一个线程上执行Runnable。
注意:不要忘记在不再需要时关闭执行程序服务,否则会阻止程序退出。
答案 1 :(得分:5)
在询问前做你的研究。我们的想法是创建一个实现Runnable的类,并使用executor服务执行它。
示例来自:Java Concurrency (Multithreading) - Tutorial
实现worker(实现Runnable):
package de.vogella.concurrency.threadpools;
/** * MyRunnable will count the sum of the number from 1 to the parameter * countUntil and then write the result to the console. * <p> * MyRunnable is the task which will be performed * * @author Lars Vogel * */
public class MyRunnable implements Runnable {
private final long countUntil;
MyRunnable(long countUntil) {
this.countUntil = countUntil;
}
@Override
public void run() {
long sum = 0;
for (long i = 1; i < countUntil; i++) {
sum += i;
}
System.out.println(sum);
}
}
如何使用执行程序服务来触发工作线程。
package de.vogella.concurrency.threadpools;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Main {
private static final int NTHREDS = 10;
public static void main(String[] args) {
//You can also use Executors.newSingleThreadExecutor() if you just need 1 thread
ExecutorService executor = Executors.newFixedThreadPool(NTHREDS);
for (int i = 0; i < 500; i++) {
Runnable worker = new MyRunnable(10000000L + i);
executor.execute(worker);
}
// This will make the executor accept no new threads
// and finish all existing threads in the queue.
executor.shutdown();
// Wait until all threads are finish
//while (!executor.isTerminated()) {
//}
//System.out.println("Finished all threads");
//All the threads might not be finished at this point of time. Thread endtime purely depends on the time taken by the processing logic inside your thread.
}
}
答案 2 :(得分:1)
你的意思是这样的吗?
class Parallel {
private ExecutorService pool = Executors.newFixedThreadPool(Runtime.getRuntime().availableProcessors());
public void shutdown() {
pool.shutdown();
}
public void foo() {
pool.submit(new Runnable() {
@Override
public void run() {
// put your code here
}
});
}
}