Question

我有一些JavaScript代码根据Ajax请求的响应对象中的各种因素创建不同的消息。例如

if (response.correct_guess === true){
    message = "your guess was correct
 }

如果用户赢了游戏，则'won'键设置为'won'

won: "won"

因此我希望像这样设置消息

else if(response.won === "won") {
          message = "You finished with" + response.seconds + "left on the clock."

然而，这个“其他如果”没有被触发

我也试过“==”（即两个等号而不是三个）。你能解释一下我做错了什么吗？

Answer 1

您的代码含义：

if (response.correct_guess === true){
    message = "your guess was correct

}else if(response.won === "won") {
      message = "You finished with" + response.seconds + "left on the clock."
}

如果猜测正确，message = "your guess was correct，就是这样。如果猜测不正确，则表示用户赢了，message = "You finished with" + response.seconds + "left on the clock."

你忘记了如果控制进入第一个if，它将永远不会到达第二个if。在if-elseif链中，第一个if / elseif块控件进入的是仅它将进入的一个。我不认为你想要那个。你可能想要：

if (response.correct_guess === true){
    message = "your guess was correct

}
if(response.won === "won") {
      message = "You finished with" + response.seconds + "left on the clock."
}

比较一个字符串

1 个答案: