Question

这应该模拟抛出的2个6面骰子，为熟悉结果的数组元素添加+1。例如：a [4]确定滚动了多少4个。出于某种原因，无论它滚动多少次，它都会为数组中的每个元素提供1。即：（a [2] = 1，a [3] = 1，a [4] = 1等）

#include <iostream>
#include <cmath>
#include <cstdlib>
#include <ctime>

using namespace std;

int throwDice()         // generates random number ranging 2-12
{
    int x = (rand() % 6) + 1;
    int p = (rand() % 6) + 1;
    return x + p;
}


int main()
{
    srand (time(NULL));
    int y;
    cout << "Roll dice how many times?" << endl;
    cin >> y;

    int a2[12];                   // initializes and declares elements a[2] - a[12] with value 0
    for (int i = 2; i <= 12; i++)
        a2[i] = 0;

    for (int i = 0; i <= y; i++)   // runs random number generator, adds +1 to that element
        {
        a2[throwDice()]++;
        }

    for (int i = 2; i <= 12; i++)   // prints how many results per element
    cout << i << " = " << throwDice[i] << endl;
    system("pause");
}

Answer 1

cout << i << " = " << throwDice[i] << endl;

应该是

cout << i << " = " << a2[i] << endl;

编译代码时应始终使用-Wall，这会立即向您显示错误：

Compilation finished with warnings:
source.cpp: In function 'int main()':
source.cpp:33:38: warning: pointer to a function used in arithmetic 
                           [-Wpointer-arith]

此外，数组索引从0开始，因此为了能够访问a2[12]，它必须至少具有13的大小。

最后，system("pause");是一个值得怀疑的想法。我希望cin.get();等待用户按任意键。

简单数组无法正常工作

1 个答案: