下午好。我有以下代码
ParseQuery query = new ParseQuery("MyOb");
query.findInBackground(new FindCallback() {
public void done(List<ParseObject> myOb, ParseException e) {
if (e == null) {
for ( i = 0; i < myOb.size(); i++) {
geo1Dub = myOb.get(i).getParseGeoPoint("location").getLatitude();
geo2Dub = myOb.get(i).getParseGeoPoint("location").getLongitude();
geo1Int = (int) (geo1Dub*1E6);
geo2Int = (int) (geo2Dub*1E6);
pointGet = new GeoPoint(geo1Int, geo2Int);
OverlayItem overlayitem = new OverlayItem(pointGet, title, title);
itemizedoverlay.addOverlay(overlayitem);
}
mapOverlays.add(itemizedoverlay);
mapView.postInvalidate();
} else {
}
}
});
从网站上,我拿点并在地图上显示。 请告诉我如何使用
distanceBetween(double startLatitude,double startLongitude,double endLatitude,double endLongitude,float [] results)
表明与我同在的观点。我的立场将在
点 point = new GeoPoint(geoLat.intValue(), geoLng.intValue());
答案 0 :(得分:1)
这不是一个非常困难的问题......您可以在此链接中找到一种方法:
答案 1 :(得分:1)
从Location
创建GeoPoints
个对象,并且您拥有distanceTO()
方法。
http://developer.android.com/reference/android/location/Location.html
float distance[] = 0.0f;
double lat = Double.valueOf(point.getLatitudeE6()/1E6);
double lat = Double.valueOf(point.getLongitudeE6()/1E6);
Location.distanceBetween(geo1Dub, geo2Dub, lat, lng, distance);
您将在变量distance[0]
答案 2 :(得分:1)
两个地理位置之间的距离: -
public static double distFrom(double lat1, double lng1, double lat2, double lng2) {
Double EARTH_RADIUS = 6371.00;
double earthRadius = EARTH_RADIUS;
double dLat = Math.toRadians(lat2-lat1);
double dLng = Math.toRadians(lng2-lng1);
double a = Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) *
Math.sin(dLng/2) * Math.sin(dLng/2);
double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
double dist = earthRadius * c;
return new Float(dist).floatValue();
}