我有TransformBlock
的以下设置:
private void SetupTestModule()
{
Func<int, int> func1 = new Func<int, int>(input =>
{
return (input + 1);
});
Func<int, int> func2 = new Func<int, int>(input =>
{
return (input + 2);
});
TransformBlock<int, int> transform = new TransformBlock<int, int>(func1);
}
我想知道在运行期间是否可以为func2交换func1以及此transformBlock和其他数据块之间的所有链接是否都将保持不变?理想情况下,在交换Funcs时,我只希望将新转换应用于所有新传入的项目。显然,使用这种简单的方法,我不会假设当前在队列中的项目以及如何处理它们。我只是想知道分配新的Func是否会导致运行时错误或者导致transformBlock被取消链接。谁可以分享一些见解?
编辑:在这里发布Jon的建议和代码一些非常基本的测试代码。让我好奇的是它可以使用和不使用volatile
关键字。我们为什么需要volatile
?
public class TransformBlockHotSwap
{
private TransformBlock<int, int> transformBlock;
private ActionBlock<int> actionBlock;
public TransformBlockHotSwap()
{
SwappableFunction<int, int> swappable = new SwappableFunction<int, int>(item => item + 1);
transformBlock = new TransformBlock<int, int>(item => swappable.Execute(item));
actionBlock = new ActionBlock<int>(item => Console.WriteLine(item));
transformBlock.LinkTo(actionBlock);
Func<int, int> func2 = new Func<int,int>(item => item * item);
for (int index = 1; index <= 100; index++)
{
transformBlock.Post(index);
Thread.Sleep(500);
if (index == 5)
{
swappable.Swap(func2);
}
}
}
}
public class SwappableFunction<TInput, TOutput>
{
private Func<TInput, TOutput> func;
public SwappableFunction(Func<TInput, TOutput> func)
{
this.func = func;
}
public void Swap(Func<TInput, TOutput> newFunc)
{
func = newFunc;
}
public TOutput Execute(TInput input)
{
return func(input);
}
}
编辑(包括谓词交换):
public class TransformBlockHotSwap
{
private TransformBlock<int, int> transformBlock;
private ActionBlock<int> actionBlock;
public TransformBlockHotSwap()
{
Func<int, int> defaultFunction = new Func<int, int>(item => item);
Func<int, int> func2 = new Func<int, int>(item => item * item);
Predicate<int> defaultPredicate = new Predicate<int>(item => true);
Predicate<int> pred2 = new Predicate<int>(item =>
{
if (item % 2 == 0)
{
return true;
}
else
{
return false;
}
});
SwappableFunction<int, int> swappableFunction = new SwappableFunction<int, int>(defaultFunction);
SwappablePredicate<int> swappablePredicate = new SwappablePredicate<int>(defaultPredicate);
transformBlock = new TransformBlock<int, int>(item => swappableFunction.Execute(item));
actionBlock = new ActionBlock<int>(item => Console.WriteLine(item));
transformBlock.LinkTo(actionBlock, item => swappablePredicate.Execute(item));
for (int index = 1; index <= 100; index++)
{
transformBlock.Post(index);
if (index == 10)
{
swappablePredicate.Swap(pred2);
}
Thread.Sleep(200);
}
Console.WriteLine("Done");
Console.ReadKey();
}
}
public class SwappableFunction<TInput, TOutput>
{
private volatile Func<TInput, TOutput> func;
public SwappableFunction(Func<TInput, TOutput> defaultFunction)
{
this.func = defaultFunction;
}
public void Swap(Func<TInput, TOutput> newFunc)
{
func = newFunc;
}
public TOutput Execute(TInput input)
{
return func(input);
}
}
public class SwappablePredicate<TInput>
{
private volatile Predicate<TInput> predicate;
public SwappablePredicate(Predicate<TInput> defaultPredicate)
{
this.predicate = defaultPredicate;
}
public void Swap(Predicate<TInput> newPredicate)
{
predicate = newPredicate;
}
public bool Execute(TInput input)
{
return predicate(input);
}
}
答案 0 :(得分:3)
我不希望你能够这样做 - 但你可以轻松地写一个委托的函数:
public class SwappableFunction<TInput, TOutput>
{
private volatile Func<TInput, TOutput> func;
public SwappableFunction(Func<TInput, TOutput> func)
{
this.func = func;
}
public void Swap(Func<TInput, TOutput> newFunc)
{
func = newFunc;
}
public TOutput Execute(TInput input)
{
return func(input);
}
}
然后:
var swappable = new SwappableFunction<int, int>(input => input + 1);
var block = new TransformBlock<int, int>(swappable.Execute);
// Later...
swappable.Swap(input => input + 2);
重要 - 我不是100%肯定在这里使用volatile
- 我通常不喜欢使用volatile
,因为它的语义令人困惑。使用Interlocked.CompareExchange
可能会更好 - 但代码会更长,我希望首先得到主要观点:)