如何在if else语句验证中不显示字符串中的第一条消息

时间:2013-02-16 04:23:11

标签: php

我的代码检查是否有任何字段未输入,然后检查验证问题是当没有错误时它仍然显示第一个error_message。=

E.g

$error_message .= "<div class=\"error-header\">Error: You did not submit the following required information.</div>";
    $error_message .= "<ul id=\"errors\">"
// this part in the second else statement always shows how do i stop that;

完整代码:

if((!$email_address)||(!$password)||(!$confirm_password)||(!$first_name)||(!$last_name)||(!$address)||(!$postal_code)||(!$region)||(!$country)) {           
        $error_message .= "<div class=\"error-header\">Error: You did not submit the following required information.</div>";
        $error_message .= "<ul id=\"errors\">";
        if(!$email_address) {
            $error_message .= "<li>Please enter you're email address.</li>";
        }
        etc...
}else {
        $error_message .= "<div class=\"error-header\">Error: The following information is invalid.</div>";
        $error_message .= "<ul id=\"errors\">";

        if($row_count > 0) {
            $error_message .= "<li>The email address you provided is already in use, please use another email address.</li>";
        }

        if($confirm_password != $password) {
            $error_message .= "<li>The passwords do not match.</li>";   
        }

        if(!isset($_POST["interests"]) || count($_POST["interests"]) < 3) {
            $error_message .= "<li>Please choose three departments that are of interest to you.</li>";                              
        }else{
            $interests = $_POST["interests"];
        }

        if(strtolower($captcha_code) == strtolower((string)$_SESSION["captcha"])) {
            $error_message .= "<li>The code you entered is incorrect.</li>";    
        }

        $error_message .= "</ul>";
     }

3 个答案:

答案 0 :(得分:2)

稍微修改了你的代码:

if((!$email_address)||(!$password)||(!$confirm_password)||(!$first_name)||(!$last_name)||(!$address)||(!$postal_code)||(!$region)||(!$country)) {           
            $error_message .= "<div class=\"error-header\">Error: You did not submit the following required information.</div>";
            $error_message .= "<ul id=\"errors\">";
            if(!$email_address) {
                $error_message .= "<li>Please enter you're email address.</li>";
            }
            etc...
    }else {

            $error_message=""; 

            if($row_count > 0) {
                $error_message .= "<li>The email address you provided is already in use, please use another email address.</li>";
            }

            if($confirm_password != $password) {
                $error_message .= "<li>The passwords do not match.</li>";   
            }

            if(!isset($_POST["interests"]) || count($_POST["interests"]) < 3) {
                $error_message .= "<li>Please choose three departments that are of interest to you.</li>";                              
            }else{
                $interests = $_POST["interests"];
            }

            if(strtolower($captcha_code) == strtolower((string)$_SESSION["captcha"])) {
                $error_message .= "<li>The code you entered is incorrect.</li>";    
            }

             //check if there is any error message, then create the div
             if(!empty($error_message))
            {
               $errorMessageLi=$error_message;
               $error_message= "<div class=\"error-header\">Error: The following information is invalid.</div>";
              $error_message .= "<ul id=\"errors\">";

              $error_message .=  $errorMessageLi;

              $error_message .= "</ul>";
            }
         }

答案 1 :(得分:0)

在我看来,这总是被执行。您需要控制何时显示$error_message(此处未显示),或者您需要对该else块进行一些检查,以确定您是否实际触及了任何if语句。

if (!($row_count = 0) && !($confirm_password != $password) && ...) {$error_message .= "";}

这将是一种笨重的方式;你可以很容易地检查最后是否添加了<li>,如果没有,请清除它;或者将一个计数器变量放入并在每个if块中递增(如果为真)。

答案 2 :(得分:0)

我倾向于使用数组来做这些事情:

$errors = array();

if (condition1) {
   $errors[] = 'condition 1 was not met';
}

if (condition2) {
  $errors[] = 'condition 2 was not met';
}
etc...

if (count($errors) > 0) {
   display error messages
}