Question

我的SQL查询出了什么问题？

它在WHERE building_id=:building_id：

处不断返回以下错误

您的SQL语法有错误;检查手册对应于您的MySQL服务器版本，以便使用正确的语法 '附近'：building_id和WHERE NOT EXISTS（从ts_roompref中选择1）在第5行：SELECT COUNT（*）totalCount FROM ts_room WHERE building_id =：building_id AND WHERE NOT EXISTS（SELECT 1 FROM ts_roompref JOIN ts_request ON ts_roompref.request_id = ts_request.roompref_id AND day_id = 1 AND period_id = 1 WHERE ts_room.id = ts_roompref.room_id）

这是我的代码：

SELECT 
  COUNT(*) totalCount 
FROM 
  ts_room 
WHERE building_id=:building_id AND
WHERE 
  NOT EXISTS (
    SELECT 1
    FROM ts_roompref 
      JOIN ts_request 
      ON ts_roompref.request_id = ts_request.roompref_id
      AND day_id = 1 
      AND period_id = 1
    WHERE 
      ts_room.id = ts_roompref.room_id)

我在这里有一个SQL表 - http://sqlfiddle.com/#!2/30297/8

Answer 1

只需删除第二个WHERE关键字。

由于:buildingid而无法在SQL Fiddle中编译。

Here's a working example

Answer 2

在AND

之后不需要第二个WHERE

... WHERE building_id=:building_id AND NOT EXISTS ...

Answer 3

您只需要一个WHERE

SELECT 
  COUNT(*) totalCount 
FROM 
  ts_room 
WHERE building_id=:building_id AND

  NOT EXISTS (
    SELECT 1
    FROM ts_roompref 
      JOIN ts_request 
      ON ts_roompref.request_id = ts_request.roompref_id
      AND day_id = 1 
      AND period_id = 1
    WHERE 
      ts_room.id = ts_roompref.room_id)

Answer 4

在AND之后，你不应该第二次写WHERE。

难以在SQL查询中放置2个WHERE

4 个答案: