如何在JTable中渲染JTable?

时间:2013-02-15 21:30:30

标签: java swing user-interface jtable nested

我正在尝试将JTable嵌套在另一个JTable的列中(使用CellRenderer)。

示例(错误)输出:

enter image description here

为什么以下示例不在表中输出表?

import java.awt.Component;

import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.table.AbstractTableModel;
import javax.swing.table.TableCellRenderer;

public class Test {

    public static void main(String[] args) {
        JTable table = new JTable(new CustomTableModel());
        table.setDefaultRenderer(Person.class, new CustomRenderer());
        JPanel panel = new JPanel();
        panel.add(new JScrollPane(table));
        JFrame frame = new JFrame();
        frame.setContentPane(panel);
        frame.pack();
        frame.setVisible(true);
    }
}

@SuppressWarnings("serial")
class CustomTableModel extends AbstractTableModel {

    @Override
    public int getColumnCount() {
        return 2;
    }

    @Override
    public int getRowCount() {
        return 1;
    }

    @Override
    public Object getValueAt(int row, int col) {
        if (col == 0) {
            return new Person("Bob");
        } else {
            return "is awesome!";
        }
    }
}

@SuppressWarnings("serial")
class CustomRenderer extends JPanel implements TableCellRenderer {

    @Override
    public Component getTableCellRendererComponent(JTable table, Object value,
            boolean isSelected, boolean hasFocus, int row, int col) {
        JTable t = new JTable(new CustomTableModel());
        add(new JScrollPane(t));
        return this;
    }
}

class Person {

    public String name = "";

    public Person(String name) {
        this.name = name;
    }
}

1 个答案:

答案 0 :(得分:4)

不要将子表添加到滚动窗格。相反,尝试将表格添加到带有BorderLayout的JPanel的中心位置,然后将表格标题添加到NORTH位置

主要原因是滚动窗格不是交互式的,可能会隐藏数据

<强>更新

我正在打电话,因此很难阅读代码:P

在主表模型中,您需要覆盖getColumnClass方法,并确保为所需列重新调整Person.class(以及其他列的正确类类型)