我使用Codeigniter的Upload Class将图像上传到项目中的文件夹。在数据库中我只存储上传图像后生成的url,所以当我想删除db中的一行时我还需要删除图像。我怎么能在codeigniter中做到这一点?
我将很感激你的答案。
答案 0 :(得分:10)
您可以使用此uploads
函数删除给定路径中的所有文件,例如deleteFiles()
文件夹中的文件,该函数可能位于您的某个模型中:
$path = $_SERVER['DOCUMENT_ROOT'].'/uploads/';
function deleteFiles($path){
$files = glob($path.'*'); // get all file names
foreach($files as $file){ // iterate files
if(is_file($file))
unlink($file); // delete file
//echo $file.'file deleted';
}
}
答案 1 :(得分:3)
delete_row_from_db(); unlink('/path/to/file');
/ path / to / file必须是真实路径。
例如:
如果你的文件夹是这样的htp://example.com/uploads
$ path = realpath (APPPATH。'../ uploads');
APPPATH =应用程序文件夹的路径。
它的工作......
答案 2 :(得分:1)
if(isset($ _ FILES ['image'])&& $ _FILES ['image'] ['name']!='') {
$config['upload_path'] = './upload/image';
$config['allowed_types'] = 'jpeg|jpg|png';
$config['file_name'] = base64_encode("" . mt_rand());
$this->load->library('upload', $config);
$this->upload->initialize($config);
if (!$this->upload->do_upload('image'))
{
$error = array('error' => $this->upload->display_errors());
$this->session->set_flashdata('msg', 'We had an error trying. Unable upload image');
}
else
{
$image_data = $this->upload->data();
@unlink("./upload/image/".$_POST['prev_image']);
$testData['image'] = $image_data['file_name'];
}
}
答案 3 :(得分:0)
$m_img_real= $_SERVER['DOCUMENT_ROOT'].'/images/shop/real_images/'.$data['settings']->shop_now;
$m_img_thumbs = $_SERVER['DOCUMENT_ROOT'].'/images/shop/thumbs/'.$data['settings']->shop_now;
if (file_exists($m_img_real) && file_exists($m_img_thumbs))
{
unlink($m_img_real);
unlink($m_img_thumbs);
}
答案 4 :(得分:0)
查看:
<input type="file" name="new_file" data-required="1" class="" />
<input type="hidden" name="old_file" value="echo your old file name"/>
<input type="submit" name="submit"/>
控制器:
function edit_image() {
if(isset($_FILES['new_file']['name']) && $_FILES['new_file']['name'] != '') {
move_uploaded_file($_FILES['new_file']['tmp_name'],'./public_html/banner/'.$_FILES['new_file']['name']);
$upload = $_FILES['new_file']['name'];
$name = $post['old_file'];
@unlink("./public_html/banner/".$name);
}
else {
$upload = $post['old_file'];
}
}
答案 5 :(得分:0)
尝试使用CI框架本身提供的delete_files('path')
功能:
https://ellislab.com/codeigniter/user-guide/helpers/file_helper.html
答案 6 :(得分:0)
$image_data = $this->upload->data();
unlink($image_data['full_path']);
此行$this->upload->data()
将返回有关上传文件的许多信息。您可以打印信息并相应地工作。